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Norma-Jean [14]
3 years ago
6

Select the correct answer. Which statement about the relationship between laws, hypotheses, and theories is true?

Chemistry
1 answer:
shusha [124]3 years ago
8 0

If a hypothesis is not contradicted after a lot of testing, it may be considered a law.

Explanation:

If a hypothesis is not contradicted after a lot of testing, it can be considered a law is a true and correct statement. Laws and theories are completely different approaches in a scientific method.

  • Laws are generalized prediction of scientific observations within a limit. Laws holds true when certain parameters are right and correct.
  • Theories are explanation of scientific phenomenon. They provide reasons why a certain observation is right or false.
  • Both laws and theories are products of hypothesis.
  • A hypothesis is a scientific guess or a tentative explanation into an investigation.
  • It must be falsifiable, repeated and testable.
  • When a hypothesis survives being repeated or tested or falsified, its status is elevated to that of a law or a theory.

Learn more:

hypothesis brainly.com/question/3418951

experiments brainly.com/question/5096428

#learnwithBrainly

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Using the following data, determine the standard cell potential E^o cell for the electrochemical cell constructed using the foll
Nana76 [90]

Answer: C)  0.637 V

Explanation:

The balanced redox reaction is:

Zn(s)+Pb^{2+}(aq)\rightarrow Zn^{2+}(aq)+Pb(s)

Here Zn undergoes oxidation by loss of electrons, thus act as anode. Lead undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

Zn^{2+}(aq)+2e^-\rightarrow Zn(s)= -0.763

Pb^{2+}(aq)+2e^-\rightarrow Pb(s)= -0.126

E^0_{[Zn^{2+}/Zn]}=-0.763V

E^0_{[Pb^{2+}/Pb]}=-0.126V

E^0=E^0_{[Pb^{2+}/Pb]}- E^0_{[Zn^{2+}/Zn]}

E^0=-0.126-(-0.763V)=0.637V

The standard emf of a cell is 0.637 V

8 0
3 years ago
A sample of a substance was determined and contained 1.0g of mg and 1.75g of o. what is the empirical formula? (10 pts)
Juliette [100K]
<span>Total mass = 2.75g Mass % of Mg = 1.0g x 100/2.75g = 36.36 % Mass % of O = 1.75g x 100/2.75g = 63.64 % Mol of Mg = 36.36/24 = 1.515 Mol of O = 63.64/16 = 3.977 Ratio of Mol of Mg and O in the substance = (1.515 : 3.977) x 2 = 3 : 8 The empirical formula of substance is Mg3O8</span>
7 0
4 years ago
A large flask is evacuated and weighed, filled with argon gas, and then reweighed. When reweighed, the flask is found to have ga
Elden [556K]

Answer:

100.52

Explanation:

from the ideal gas equation PV=nRT

for a given container filled with any ideal gas P and V remains constant.So T is also constant.R is as such a constant.

So n i.e no of moles will also be constant.

no of moles of Ar=3.224/40=0.0806

no of moles of unknown gas=0.0806

molecular wt of unknown gas=8.102/0.0806=100.52

8 0
3 years ago
What do sodium and magnesium have in common?
lara [203]

Answer:

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Explanation:

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7 0
3 years ago
To indicate the pH of a substance, one can use a dye that is both an acid and that appears as different colors in its protonated
PIT_PIT [208]

Answer:

<em>The pH of the solution is 7.8</em>

Explanation:

The concentration of the solution is 0.001M and  the dye could be in its protonated and deprotonated forms. If the concentration of the protonated form [HA] is 0.0002 M the concentration of the deprotonated form will be the subtraction between the concentration of the bye and the concentration of the protonated form:

[A-] = 0.001M - 0.0002M = 0.0008M

Also, the Henderson-Hasselbalch equation is

pH = pKa + Log \frac{[A^{-}]}{[HA]}

this equation shows the dependency between the pH of the solution, the pKa and the concentration of the protonated and deprotonated forms. Thus, replacing in the equation

pH = 7.2 + Log \frac{0.0008M}{0.0002M} = 7.8

3 0
3 years ago
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