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3 years ago

Select the correct answer. Which statement about the relationship between laws, hypotheses, and theories is true?

Chemistry

1 answer:

shusha [124]3 years ago

8 0

If a hypothesis is not contradicted after a lot of testing, it may be considered a law.

Explanation:

If a hypothesis is not contradicted after a lot of testing, it can be considered a law is a true and correct statement. Laws and theories are completely different approaches in a scientific method.

Laws are generalized prediction of scientific observations within a limit. Laws holds true when certain parameters are right and correct.
Theories are explanation of scientific phenomenon. They provide reasons why a certain observation is right or false.
Both laws and theories are products of hypothesis.
A hypothesis is a scientific guess or a tentative explanation into an investigation.
It must be falsifiable, repeated and testable.
When a hypothesis survives being repeated or tested or falsified, its status is elevated to that of a law or a theory.

Learn more:

hypothesis brainly.com/question/3418951

experiments brainly.com/question/5096428

#learnwithBrainly

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Using the following data, determine the standard cell potential E^o cell for the electrochemical cell constructed using the foll

Nana76 [90]

Answer: C) 0.637 V

Explanation:

The balanced redox reaction is:

$Zn(s)+Pb^{2+}(aq)\rightarrow Zn^{2+}(aq)+Pb(s)$

Here Zn undergoes oxidation by loss of electrons, thus act as anode. Lead undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$Zn^{2+}(aq)+2e^-\rightarrow Zn(s)$ = -0.763

$Pb^{2+}(aq)+2e^-\rightarrow Pb(s)$ = -0.126

$E^0_{[Zn^{2+}/Zn]}=-0.763V$

$E^0_{[Pb^{2+}/Pb]}=-0.126V$

$E^0=E^0_{[Pb^{2+}/Pb]}- E^0_{[Zn^{2+}/Zn]}$

$E^0=-0.126-(-0.763V)=0.637V$

The standard emf of a cell is 0.637 V

8 0

3 years ago

A sample of a substance was determined and contained 1.0g of mg and 1.75g of o. what is the empirical formula? (10 pts)

Juliette [100K]

<span>Total mass = 2.75g Mass % of Mg = 1.0g x 100/2.75g = 36.36 % Mass % of O = 1.75g x 100/2.75g = 63.64 % Mol of Mg = 36.36/24 = 1.515 Mol of O = 63.64/16 = 3.977 Ratio of Mol of Mg and O in the substance = (1.515 : 3.977) x 2 = 3 : 8 The empirical formula of substance is Mg3O8</span>

7 0

4 years ago

A large flask is evacuated and weighed, filled with argon gas, and then reweighed. When reweighed, the flask is found to have ga

Elden [556K]

Answer:

100.52

Explanation:

from the ideal gas equation PV=nRT

for a given container filled with any ideal gas P and V remains constant.So T is also constant.R is as such a constant.

So n i.e no of moles will also be constant.

no of moles of Ar=3.224/40=0.0806

no of moles of unknown gas=0.0806

molecular wt of unknown gas=8.102/0.0806=100.52

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3 years ago

What do sodium and magnesium have in common?

lara [203]

Answer:

daddy will help

Explanation:

uhhhhhhhhhhhhhhhhhhh

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3 years ago

To indicate the pH of a substance, one can use a dye that is both an acid and that appears as different colors in its protonated

PIT_PIT [208]

Answer:

<em>The pH of the solution is 7.8</em>

Explanation:

The concentration of the solution is 0.001M and the dye could be in its protonated and deprotonated forms. If the concentration of the protonated form [HA] is 0.0002 M the concentration of the deprotonated form will be the subtraction between the concentration of the bye and the concentration of the protonated form:

[A-] = 0.001M - 0.0002M = 0.0008M

Also, the Henderson-Hasselbalch equation is

$pH = pKa + Log \frac{[A^{-}]}{[HA]}$

this equation shows the dependency between the pH of the solution, the pKa and the concentration of the protonated and deprotonated forms. Thus, replacing in the equation

$pH = 7.2 + Log \frac{0.0008M}{0.0002M} = 7.8$

3 0

3 years ago