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Sergeu [11.5K]
3 years ago
12

Which of the following chemical equations show(s) oxidation-reduction reactions?1. Mg(s) + I2(aq) --> MgI2(s)2. Pb(ClO4)2(aq)

+ 2 KI(aq) --> PbI2(s) + 2 KClO4(aq)3. Fe2O3(s) + 3 CO(g) --> 2 Fe(s) + 3 CO2(g)1 only2 only1 and 21 and 32 and 3
Chemistry
1 answer:
maksim [4K]3 years ago
6 0

Answer : The correct option is, 1 and 3

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

(1) The given balanced chemical reaction is :

Mg(s)+I_2(aq)\rightarrow MgI_2(s)

The oxidation-reduction half reaction will be :

Oxidation : Mg\rightarrow Mg^{2+}+2e^-

Reduction : I_2+2e^-\rightarrow 2I^-

In this reaction, the oxidation state of 'Mg' changes from (0) to (+2) that means Mg lost 2 electrons and it shows oxidation and the oxidation state of 'I' changes from (0) to (-2) that means 'I' gains 2 electrons and it shows reduction.

(2) The given balanced chemical reaction is :

Pb(ClO_4)_2(aq)+2KI(aq)\rightarrow PbI_2(s)+2KClO_4(aq)

In this reaction does not shows oxidation reduction reaction. This reaction shows double displacements and in this reaction the oxidation state of lead, iodine, potassium and chlorate does not change.

(3) The given balanced chemical reaction is :

Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)

The oxidation-reduction half reaction will be :

Oxidation : C^{2+}\rightarrow C^{4+}+2e^-

Reduction : Fe^{3+}+3e^-\rightarrow Fe

In this reaction, the oxidation state of 'C' changes from (+2) to (+4) that means C lost 2 electrons and it shows oxidation and the oxidation state of 'Fe' changes from (+3) to (0) that means 'Fe' gains 3 electrons and it shows reduction.

Hence, the chemical equations show(s) oxidation-reduction reactions are, 1 and 3.

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Wskaż substancję, która ma największą zawartość procentową węgla w cząsteczce:
MrRa [10]

Answer: C2H4

Explanation:

The percentage composition of ethanol ( C2H5OH ) consist of 52.2% Carbon, Hydrogen of 13.0 and 34.8% of Oxygen.

The percentage composition of ethane gas (C2H6) consist of 80.0% carbon and 20.0% hydrogen.

The composition of Ethylene Glycols i.e C2H4(OH)2 is Carbon of 39.7%, 9.7% hydrogen and 51.6% oxygen.

The percent composition of c2h4 is 86% carbon, and 14% hydrogen.

From the information given, the substance with the highest percentage of carbon is C2H4

7 0
3 years ago
calculate the difference in slope of the chemical potential against temperature on either side of the normal freezing point of w
kipiarov [429]

Answer:

(a) The normal freezing point of water (J·K−1·mol−1) is -22Jmole^-^1k^-^1

(b) The normal boiling point of water (J·K−1·mol−1) is -109Jmole^-^1K^-^1

(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is  109J/mole

Explanation:

Lets calculate

(a) - General equation -

      (\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p = -5_m(\beta )+5_m(\alpha ) =  -\frac{\Delta H}{T}

 \alpha ,\beta → phases

ΔH → enthalpy of transition

T → temperature transition

 (\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p == -\frac{\Delta_fH}{T_f}

            = \frac{-6.008kJ/mole}{273.15K} ( \Delta_fH is the enthalpy of fusion of water)

           = -22Jmole^-^1k^-^1

(b) (\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}

                                  = \frac{40.656kJ/mole}{373.15K} (\Delta_v_a_p_o_u_rH is the enthalpy of vaporization)

                               = -109Jmole^-^1K^-^1

(c) \Delta\mu =\Delta\mu(l)-\Delta\mu(s) =-S_m\DeltaT

[\mu(l-5°C)-\mu(l,0°C)] =  [\mu(s-5°C)-\mu(s,0°C)]=-S_mΔT

\mu(l,-5°C)-\mu(s,-5°C)=-Sm\DeltaT [\mu(l,0

\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)

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6 0
2 years ago
In an experiment, students were given an unknown mineral. The unknown mineral was placed in 150 ml of water. Once in the water,
Dahasolnce [82]

Answer:

<h2>15 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

But from the question

volume = final volume of water - initial volume of water

volume = 165 - 150 = 15 mL

We have

density =  \frac{225}{15}  = 15 \\

We have the final answer as

<h3>15 g/mL</h3>

Hope this helps you

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IrinaK [193]

Answer: Double displacement reaction

Explanation:

Double displacement reaction is defined as the reaction where exchange of ions takes place.

The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The chemical reaction between aqueous magnesium sulfate and aqueous sodium carbonate is represented as:

MgSO_4(aq)+Na_2CO_3(aq)\rightarrow Na_2SO_4(aq)+MgCO_3(s)

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3 years ago
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Ksju [112]
Answer: B


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