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3 years ago

5 grams is thes than greater than or equal too 508mg

Physics

2 answers:

guapka [62]3 years ago

7 0

Answer:

yes 5 is greater

Explanation:

makkiz [27]3 years ago

4 0

Answer: 5 grams is greater than 508 milligrams. Even though the number '508' is larger than '5,' you need to look at the units.

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Which contemporary subfield focuses on assessing and treating people with mental disorders?

Vlada [557]

Psychiatry assesses and treats people with mental disorders

3 0

3 years ago

a coil of 40 henry inductance is connected in series with aresistance of 8ohm and the combination is joined to the terminals of

Andreyy89

Answer: 5 seconds

Explanation:

Given the following :

Inductance (L) = 40 henry

Resistance = 8 ohms

The circuit given above is a Resistor - Inductor (RL) circuit network. The time constant of an RL circuit is the ratio of the circuit Inductance (L) and Resistance (R). Time constant is measured in seconds.

THAT IS;

Time constant = L / R

THEREFORE ;

Time constant = 40 / 8

Time constant = 5 seconds

7 0

3 years ago

A speaker is designed for wide dispersion for a high frequency sound. What should the diameter of the circular opening be for a

andriy [413]

To solve this problem we will apply the concepts related to wavelength, as well as Rayleigh's Criterion or Optical resolution, the optical limit due to diffraction can be calculated empirically from the following relationship,

$sin\theta = 1.22\frac{\lambda}{d}$

Here,

$\lambda$ = Wavelength

d= Diameter of aperture

$\theta$ = Angular resolution or diffraction angle

Our values are given as,

$\theta = 11\°$

The frequency of the sound is $f = 9100 Hz$

The speed of the sound is $v = 343 m/s$

The wavelength of the sound is

$\lambda = \frac{v}{f}$

Here,

v = Velocity of the wave

f = Frequency

Replacing,

$\lambda = \frac{(343 m/s)}{(9100 Hz)}$

$\lambda = 0.0377 m$

The diffraction condition is then,

$sin\theta = 1.22\frac{\lambda}{d}$

Replacing,

$sin(11\°) = 1.22\frac{(0.0377 m)}{(d)}$

d = 0.24 m

Therefore the diameter should be 0.24m

6 0

3 years ago

Hi, please help me this question

ss7ja [257]

3. Plastic rubbed in hair would make the plastic negatively charged and the hair positively charged. This means that the attractive force between the paper and plastic is greater than the repulsive force between paper and plastic. The net result is an attraction between the paper and the plastic.

5 0

3 years ago

A cylindrical conductor with a circular cross section has a radius a and a resistivity p and carries a constant current I. (Take

Lady bird [3.3K]

Answer:

Explanation:

Using Ohms Law

$R= \rho \frac{l}{\pi a^2 }
\\V = IR = E l = I \rho \frac{l}{\pi a^2 }
\\E = \frac{I \rho}{\pi a^2 }
\\E = J \rho
$

Where J is the current density $J = \frac{I}{\pi a^2 }
$

and the direction of E is the same as the direction of the current. Since J is uniform throughout the conductor $E = \rhoJ$ just inside at a radius a (and anywhere else).

Since we have no changing electric fields we can use Ampere’s law in it’s simplest form without displacement current

$\oint B .dl = B 2 \pi a = \mu_{o} I
$

such that

$B = \frac{\mu_{o} I}{2 \pi a }
$

and by the right hand rule, since the current is going to the right, the magnetic field is circling around the conductor such that it’s pointing out of the page at the top and into the page at the bottom.

The Poynting vector is given by

$S = \frac{1}{ \mu_o} |E \textrm{x}B| = \frac{\rho I^2}{2 \pi^2 a^3}
$

and by the right hand rule it’s always pointing in towards the center of the conductor.

Note: directions of these three vectors are mentioned along with their magnitudes in above 3 parts a , b and c

7 0

3 years ago