Answer:
the answer would be A and B
Answer:
m = 0.25
Explanation:
Given that,
Object distance, u = -15cm
Height of the object, h = 48
Focal length, f = cm
We need to find the magnification of the image.
Let v is the image distance. Using mirror's equation.
Magnification,
Hence, the magnification of the image is 0.25.
Answer:
d=1.07m
Explanation:
Calculate Initial Kinetic Energy:
KE = 1/2*m*v^2
KE= 0.5*(10.3kg)*(1.64m/s)^2 = 13.85J
Calculate work overcoming friction:
W = F*d = mu*m*g*d
W = (0.128)*(10.3kg)*9.80m/s^2)*d
W = 12.92*d
Equate the two since all of the kinetic energy is used up in working against friction:
W = KE
12.92d = 13.851J
Solve for d:
d= (13.851J)/(12.92) = 1.07 m
Answer:
v2^2 - v1^2 = 2 g s fundamental formula
v2 = v1 + 2 g = v1 + 19.8 increase in velocity in 2 sec
v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76
v1 = (2412.76 - 392) / 39.6 = 51.03
v2 = 51.03 + 19.6 = 70.63
T = 70.63 / .8 = 7.207 sec time to fall height of tower
S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m
(Note v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m
2385 / (2 * 9.8) = 122 m (close to 123.1 as was given
