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Pie
2 years ago
10

How many moles of carbon dioxide are present in 14g of co2

Chemistry
1 answer:
Tomtit [17]2 years ago
8 0

0.32 moles

You just do 14/ 44.01 (the atomic mass of carbon + oxygen's atomic massX2)

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For the reaction2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H2O (g)ΔH° is -125 kJ/mol and ΔS° is +253 J/K ∙ mol. This reaction is _
ivanzaharov [21]

Answer:

C. spontaneous at all temperatures

Explanation:

The spontaneity of  reaction is determined by the sign of the  gibbs free energy.

A negative sign denotes that the reaction is spontaneous, positive sign means the reaction is not spontaneous.

From the question;

ΔS° = +253 J/K

ΔH° = -125 kJ/mol

ΔG = ΔH°  - TΔS°

From the data given, the condition in which we can obtain a negative value of G, is at any value of T.

For any value of T, G would always be a negative value.

This means the correct option is option C.

3 0
3 years ago
Suppose an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron. Comple
AfilCa [17]

Explanation:

An alpha particles is basically a helium nucleus and it contains 2 protons and 2 neutrons.  

Symbol of an alpha particle is ^{4}_{2}\alpha. Whereas a neutron is represented by a symbol ^{1}_{0}n, that is, it has zero protons and only 1 neutron.

Therefore, reaction equation when an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron is as follows.

        ^{27}_{13}Al + ^{1}_{0}n \rightarrow ^{30}_{15}P + ^{1}_{0}n

5 0
3 years ago
¿Qué ocurre cuando la radiación del sol atraviesa la atmósfera?
12345 [234]
Umm yo no se no ablo engles
6 0
2 years ago
I need help fast pls someone
Neko [114]

Answer:

I would say A. I'm no expert, but it can't be C obviously, and I think wind would hit all of it, wearing off the top as well like the great pyramids. B would be my next choice, but A i think would be best.

3 0
2 years ago
(GIVING BRAINLIEST) do what the following image says.
S_A_V [24]

Answer:

hope it helps.

<h3>stay safe healthy and happy.<u>.</u><u>.</u></h3>

7 0
2 years ago
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