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7nadin3 [17]
3 years ago
12

14) Worms are found all over the world under many different conditions.the would be considered as a

Biology
1 answer:
Volgvan3 years ago
5 0

Answer:

Generalist

Explanation:

 Living Organisms able to exists in different types of environment and have different types of food are called "Generalist"<u>Raccoons</u> are the best example of generalist. they are extended from North to Central America . they are able to survive even by consuming human garbage .It is this quality make them to thrive in different types of environment.

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Genetics Problems (ABO Blood System) The chart below lists the blood phenotypes of 8 individuals. Use the information in the cha
Setler79 [48]

Answer:

Explanation:

Female blood type   Male blood type

Anne Type O            Charlie Type A

Wendy Type B          Scott Type AB

Susan Type AB         Larry Type O

Patricia Type A         Keith Type B

1. Larry has a son with type B blood. Which of the females listed above could be this child's biological mother?

For Larry that is of type O to produce a son with type B blood, his mother has to be either of type B or AB. Which is either Wendy or Susan

2. Anne is pregnant with Scott's child. What is the chance that the baby will have type A blood?  

Since Scott possess the AB codominant type and Anne's type has to be inherited in the recessive form, the chances of producing type A is 50% and B is 50%. Thus, the chance that the baby will be of type A blood is 50%.

3. Because her daughter has type B blood, Patricia insists that Keith is the father. Keith claims that Scott is the father of Patricia's baby girl. Is it possible that Scott is the baby's father?  

Since Scott that is of type AB is the father of a type B child, the mother Patricia that is of A type has to have a genotype that is AO for it to be  possible that Scott is the father.

4. Keith and Wendy have a 4-year old with type O blood. How is this possible?

Keith is of type B blood and Wendy is also of type B blood. It is possible to have a 4-year old with type O blood if if both parents are of the BO genotype.

5. Susan is the mother of Charlie's first two children. The oldest, Dawn, has type AB blood while her sister, Kate, has type B blood. Charlie is now expecting a baby with Anne. What is the chance that this child will have type O blood?

Charlie and Susan can only produce Kate of type B blood if they are AO and AB respectively. Thus, since Charlie's genotype is AO, there is a 50% chance that he can produce a child of type O blood with Anne who is of type O blood.

6. Erin, Patricia and Larry's daughter, is married to Jeff. Jeff was in a serious car accident and needs a transfusion but Erin is told that Jeff cannot be given her blood. Based on this information, provide Erin's blood genotype and blood phenotype.

   For Erin to be unable to give her blood to Jeff, it means Jeff is of O blood type and Erin is not, meaning she can either be A+, B+ or AB. But since her mother is of type A and father is of O, this rules out AB and also B.  Her genotype can't be AA since her dad is of type O blood. Thus, it can be claimed that she is of genotype AO of type A blood type.

7. Scott and Susan's son, Paul, is willing to donate blood to a young girl with leukemia. If the recipient has type O blood, will Paul be able to donate to her?

Since the recipient has type O blood, she can only receive from a type O patient. Paul cannot be a donor because both parents are of AB blood type meaning Scott is either of type A, B or AB. Thus, he will not be able to donate as he is not of O type.

7 0
3 years ago
In a particular variety of corn, kernel corn is controlled by a single gene with two alleles. the dominant allele results in pur
PIT_PIT [208]

The frequency of recessive yellow beans resulting from a cross between two heterozygous plants is 25%.

<h3>What are recessive alleles?</h3>

Recessive alleles differ from dominant alleles in not being able to express themselves in heterozygotes. These alleles are only expressed in the phenotype if they are present in pairs, that is, they must be in homozygosity.

With this information, we can conclude that the frequency of recessive yellow beans resulting from a cross between two heterozygous plants is 25%.

Learn more about Recessive alleles in brainly.com/question/18075358

#SPJ1

4 0
2 years ago
Water molecules readily form hydrogen bonds with other polar molecules, and when they encounter nonpolar molecules they must for
Korolek [52]

Answer:

a. 2-methylpropane

Hope this helps :)

5 0
4 years ago
In addition to the base, what are the other components of a nucleotide?
mestny [16]
B. Phosphate and sugar. 
3 0
3 years ago
First identify the gametes. use pink labels to identify the male and female gamete types and white labels to identify the gamete
Lady bird [3.3K]
I found the whole exercise on the internet. Attached is the scheme with labels for the gametes, f2 generation, and respective frequencies.

For the gametes position, on the left pink square on the male gametes side you should put a capital G, <span>and on the right pink square on the male gametes side you should put a small g, as</span> the only two possible offsprings that are showing is "GG" under the left male gamete and "gg" under the right male gamete. On the top pink square on the female gametes side you should put a capital G, and on the bottom pink square on the female gametes side you should put a small g, as the only two possible offsprings that are showing is "GG" on the same line as the top female gamete and "gg" on the same line as the bottom female gamete.
As for the frequencies of the gametes, you should put the white label that marks 1/2 by the side of each gamete.
Related to the F2 generation, the top right and bottom left pink squares should have the label with a capital G and small g - "Gg" which reflects the combination of the male gamete on its line with the female gamete also on its line.
As for the frequencies of the progeny, each of the genotypes formed from the union of the gametes should have by the side the white label that marks 1/4.
The totals would be that GG is 1/4, Gg is 1/2 (1/4+1/4), and gg is also 1/4.

6 0
3 years ago
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