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3 years ago

Which electron configurations represent the first two elements in Group 17 (7A) of the Periodic Table?

Chemistry

2 answers:

melisa1 [442]3 years ago

7 0

Answer:a

Explanation:

SpyIntel [72]3 years ago

7 0

Answer:

Option C is correct

1s22s22p5 and [Ne]3s23p5

Explanation:

Step 1: Data given

Group 17 = the halogens

Halogens have 7 valence electrons

The first element of group 17 = Fluorine (F)

Fluorine has 9 electrons

The electron configuration is

1s2 2s2 2p5

The second element of group 17 = Chlorine (Cl)

Chlorine has 17 electrons

The electron configuration is

1s2 2s2 2p6 3s2 3p5

Option C is correct

1s22s22p5 and [Ne]3s23p5

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Density of 2.7 g/ml and volume of 35.6 ml what is the mass

Anettt [7]

The math is set up like

35.6 ml * 2.7 g/ 1 ml

which will leave you with

96.12 g

3 0

4 years ago

Convert 4.5 X 1022 molecules of H2O to moles.

noname [10]

Answer:

<h3>The answer is 0.075 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{4.5 \times {10}^{22} }{6.02 \times {10}^{23} } \\ = 0.074750830...$

We have the final answer as

<h3>0.075 moles</h3>

Hope this helps you

3 0

3 years ago

Which of the following is true about two neutral atoms of the element gold?

Nuetrik [128]

C is correct on this problem

7 0

3 years ago

Read 2 more answers

Part C: complete the third column <br> Part D: complete the fourth column

Helga [31]

Answer:

Part C: P2 = 0.30 atm

Part D: V1 = 16.22 L.

Explanation:

Part C:

Initial pressure (P1) = 2.67 atm

Initial volume (V1) = 5.54 mL

Final pressure (P2) =.?

Final volume (V2) = 49 mL

The final pressure (P2) can be obtained as follow:

P1V1 = P2V2

2.67 x 5.54 = P2 x 49

Divide both side by 49

P2 = (2.67 x 5.54)/49

P2 = 0.30 atm

Therefore, the final pressure (P2) is 0.30 atm

Part D:

Initial pressure (P1) = 348 Torr

Initial volume (V1) =?

Final pressure (P2) = 684 Torr

Final volume (V2) = 8.25 L

The initial volume (V1) can be obtained as follow:

P1V1 = P2V2

348 x V1 = 684 x 8.25

Divide both side by 348

V1 = (684 x 8.25)/348

V1 = 16.22 L

Therefore, the initial volume (V1) is 16.22 L

6 0

3 years ago

Draw the structure of the compound identified by the following simulated 1H and 13C NMR spectra. The molecular formula of the co

Luba_88 [7]

Answer: 4-allylanisole

Explanation: The doublets behind the 7 ppm belongs to the

para-substituted benzene ring. The three single-proton multi-plets around 5−6 ppm predicts that there has to be a single subsituted alkene group

A single plus a doublet around 3-4 ppm belongs to CH3 and CH2 Groups as they could be attached to the subsituted alkene group.

Moreover the interpretation of the NMR that there is no peak with a higher intensity for >180 ppm represents an absence of Carbonyl group.

The Predicted Number is attached from a chemical database along with their peaks information

6 0

3 years ago