I'll go through them one by one
1) H-S
The electronegativity of Hydrgoen is 2.2, and sulphur is 2.58,
therefore the difference is 0.38 (2.58-2.2=0.38)
2) H-Cl
Hydrogen: 2.2, Chlorine: 3.16
therefore difference is 0.96
3) N-H
Nitrogen: 3.04, Hydrogen: 2.2
therefore difference is 0.84
4) C-H
Carbon: 2.55, hydrogen: 2.2
therefore difference is 0.35
so, the most apparent electronegativity is chlorine, but this could have been done without actually doing the maths. The trend of electronegativty increases across a period and increases up a period due to the strong affinity of the nucleus with bonding electrons. This does not include noble gases though, as they have no charge due to having complete valance shells. T<span>he most electronegative element is Fluorine (9), and the least electronegative element (besides noble gases) is Francium (87)</span>
Gold is a chemical element with symbol Au (from Latin: aurum) and atomic number 79, making it one of the higher atomic number elements that occur naturally. In its purest form, it is a bright, slightly reddish yellow, dense, soft, malleable, and ductile metal.
Pure gold is soft and is usually alloyed with other metals, such as silver, copper, platinum or palladium, to increase its strength. Gold alloys are used to make jewelry, decorative items, dental fillings and coins. The amount of gold in an alloy is measured with a unit called a karat.
Charles Darwin was a Geologist, biologist and is best known for his contributions to science of evolution.
The correct option is D.
Transition metals are those metallic elements that are located in the central block of the periodic table. They exhibit various valency states and they generally have various colors. The atomic radius of an element refers to the measure of the size of its atom. For transition metals, their atomic radii decrease slightly and then start to increase, when one is moving from the left to the right of the periodic table.
Answer:
A symbiotic relationship.
I hope this helped! Brainliest would be greatly appreciated.