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3 years ago

Which of the following elements will tend to form an anion?

Chemistry

2 answers:

saul85 [17]3 years ago

7 0

Answer:

D. Silicon

Explanation:

A anion is a negatively charge ion resulting from the imbalance of protons and neutrons where there are more electrons than protons. Silicon has 4 valence electrons and is more likely to form an ionic bond with another atom(s) that will give it the 4 electrons it needs to become stable.

Nonamiya [84]3 years ago

7 0

Answer:

<h2>Please click above answer. </h2>

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faust18 [17]

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3 years ago

For the reaction below, identify the excess reactant when 4.35 g of hydrogen reacts with 30.75 g of iodine to produce hydrogen i

kogti [31]

The excess reactant when 4.35 g of hydrogen reacts with 30.75g of hydrogen iodide is hydrogen

<h3>calculation</h3>

write the equation for the reaction

H2(g) + I2 (g) → 2HI (g)

find the mole of each reactant

moles = mass/molar mass

moles of H2= 4.35 g/2 g/mol= 2.175 moles

moles o I2 = 30.75 g/ 254 g/mo=0.1211 moles

0.1211 moles of I2 reacted with 0.1211 moles of H2 but there are more moles of H2 there Hydrogen was in excess

6 0

4 years ago

I hate chemistry sm pls help

Liono4ka [1.6K]

Answer:
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5 0

3 years ago

When 1.550 g of liquid hexane (C6H14) undergoes combustion in a bomb calorimeter, the temperature rises from 25.87∘C to 38.13∘C.

AlladinOne [14]

Explanation:

1). The given data is as follows.

$T_{i} = 25.87^{o}C$ , $T_{f} = 38.13^{o}C$

C = 5.73 $kJ/^{o}C$

Hence, calculate the change in enthalpy of the reaction as follows.

$\Delta E_{rxn} = -C \times \Delta T$

= $-5.73 \times (38.13 - 25.87)^{o}C$

= -70.25 KJ

As, number of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{1.55}{(6 \times 12 + 14 \times 1)}$

= 0.018 mol

Therefore, enthalpy of reaction in kJ/mol hexane is as follows.

$\Delta E_{rxn} = \frac{-70.25 KJ}{0.018 mol}$

= $-3.90 \times 10^{3}$ kJ/mol

Thus, we can conclude that $\Delta E_{rxn}$ for the reaction in kJ/mol hexane is $-3.90 \times 10^{3}$ kJ/mol .

2). As we know that,

Number of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{1.55}{(7 \times 12 + 8 \times 1)}$

= 0.017 mol

$\Delta E_{rxn} = \E_{rxn} per mol \times \text{number of moles}$

= $-3.91 \times 10^{3} \times 0.017$

= -65.875 kJ

As, $\Delta E_{rxn} = C \times \Delta T
$

-65.875 kJ = $-C \times (37.57 - 23.12)^{o}C$

C = 4.56 $kJ/^{o}C$

Hence, heat capacity of the bomb calorimeter is 4.56 $kJ/^{o}C$ .

3 0

4 years ago

Sodium chlorate decomposes into sodium chloride and oxygen gas as seen in the equation below.

Andru [333]

Answer:

${ \rm{2\: moles \: of \: sodium \: chlorate = 2 \: moles \: of \: sodium \: choride}} \\ { \rm{10 \: moles \: of \: sodium \: chlorate = ( \frac{10}{2} \times 2) \: moles}} \\ \\ = { \boxed{ \rm{ \: 10 \: moles \: of \: sodium \: chloride}}} \\$

3 0

3 years ago

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