1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
igomit [66]
3 years ago
12

The decomposition of N2O to N2 and O2 is a first-order reaction. At 730°C, the rate constant of the reaction is 1.94 × 10-4 min-

1. If the initial pressure of N2O is 4.70 atm at 730°C, calculate the total gas pressure after one half-life. Assume that the volume remains constant. slatter
Chemistry
2 answers:
jekas [21]3 years ago
8 0

Answer:

The Total Pressure = 5.875

Explanation:

The Equation:  2N2O(g)  -> 2N2(g) + O2(g)

The rate costant is "k" of the reaction : k= 19.4 * 10^-4 min^-1

Half period = 0.693 / k

=0.693/19.4 * 10^-4 min^-1 = 3572 min

The initial pressure of N2O, Po = 4.70 atm

The pressure of N2O after 3572 min = Pt

According to the first-order kinetics:

k= 1/t  1n P0/pt

19.4 * 10^-4 min^-1 = 1/3572 min 1n 4.70atm / Pt

1n 4.70atm / Pt = 0.692968

4.70atm / Pt = e^0.692968 = 2.00

Pt = 4.70atm / 2.00 = 2.35 atm

                       2N2O(g)  -> 2N2(g) + O2(g)

The initial(atm)    4.70          0              0

The change(atm)  -2x         +2x            x

Final(atm)         4.70-2x        2x             x

Pressure of N20 after one half-life = Pt = 2.35 = 4.70-2x

Pressure of O2 after one half-life = Po = x = 1.175 atm

Pressure of O2 after one half-life = 2x = 2(1.175) = 2.35 atm

Total Pressure = 2.35 atm + 2.35 atm + 1.175 atm

= 5.875 atm

grin007 [14]3 years ago
5 0

Answer:

Total pressure 5.875 atm

Explanation:

The equation for above decomposition is

2N_2O \rightarrow 2N_2 + O_2

rate constant k =  1.94\times 10^{-4} min^{-1}

Half life t_{1/2} = \frac{0.693}{k} = 3572 min

Initial pressure N_2 O = 4.70 atm

Pressure after 3572 min = P

According to first order kinematics

k = \frac{1}{t} ln\frac{4.70}{P}

1.94\times 10^{-4} = \frac{1}{3572} \frac{4.70}{P}

solving for P we get

P = 2.35 atm

2N_2O \rightarrow 2N_2 + O_2

initial           4.70                         0             0

change        -2x                          +2x           +x

final             4.70 -2x                     2x           x

pressure ofO_2 after first half life  = 2.35 = 4.70 - 2x

                                                          x = 1.175

pressure of N_2 after first half life  =  2x = 2(1.175) = 2.35 ATM

Total pressure  = 2.35 + 2.35 + 1.175

                          = 5.875 atm

You might be interested in
An ___is usually a homologous structure that is shared by all organisms in a group~science
Paraphin [41]
A shared derived characteristics is usually a homologous structure, such as a backbone, that is shared by all organisms in a group.
8 0
3 years ago
What type of system is Earth ?
Gnoma [55]

The planet Earth itself is considered to be a closed system because there is a limit to the amount of matter that is exchanged. However, there are open systems that are ON Earth.

3 0
3 years ago
How are models useful in describing how molecules are formed
Nady [450]

Answer:

The purpose of molecular modeling is to provide a three-dimensional image (either physical or software-based) that allows a chemist to better see the manner in which atoms and molecules can interact. These models can be used to interpret existing observations or to predict new chemical behavior.

Explanation:

It can describe shape and how they connect while forming the electrons.

6 0
3 years ago
A 0.245-L flask contains 0.467 mol co2 at 159 °c. Calculate the pressure using the ideal gas law.
lubasha [3.4K]

Answer:

Pressure, P = 67.57 atm

Explanation:

<u>Given the following data;</u>

  • Volume = 0.245 L
  • Number of moles = 0.467 moles
  • Temperature = 159°C
  • Ideal gas constant, R = 0.08206 L·atm/mol·K

<u>Conversion:</u>

We would convert the value of the temperature in Celsius to Kelvin.

T = 273 + °C

T = 273 + 159

T = 432 Kelvin

To find the pressure of the gas, we would use the ideal gas law;

PV = nRT

Where;

  • P is the pressure.
  • V is the volume.
  • n is the number of moles of substance.
  • R is the ideal gas constant.
  • T is the temperature.

Making P the subject of formula, we have;

P = \frac {nRT}{V}

Substituting into the formula, we have;

P = \frac {0.467*0.08206*432}{0.245}

P = \frac {16.5551}{0.245}

<em>Pressure, P = 67.57 atm</em>

4 0
3 years ago
For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell potential at 25 ∘C if the concentrations are [
sveta [45]

Explanation:

The given data is as follows.

     E^{o} = 0.483,     [Co^{3+}] = 0.173 M,

     [Co^{2+}] = 0.433 M,     [Cl^{-}] = 0.306 M,

     P_{Cl_{2}} = 9.0 atm

According to the ideal gas equation, PV = nRT

or,             P = \frac{n}{V}RT    

Also, we know that

                Density = \frac{mass}{volume}

So,         P = MRT

and,          M = \frac{P}{RT}

                    = \frac{9.0 atm}{0.0820 L atm/mol K \times 298 K}

                    = \frac{9.0}{24.436}

                    = 0.368 mol/L

Now, we will calculate the cell potential as follows.

          E = E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}

             = 0.483 - \frac{0.0591}{2} log \frac{(0.433)^{2}(0.368)}{(0.173)(0.306)^{2}}

             = 0.483 - 0.02955 log \frac{0.0689}{0.0162}

             = 0.483 - 0.02955 \times 0.628

             =  0.483 - 0.0185

             = 0.4645 V

Thus, we can conclude that the cell potential of given cell at 25^{o}C is 0.4645 V.

4 0
3 years ago
Other questions:
  • How will you show the presence of water vapour in air?
    15·2 answers
  • What does the the release or absorption of energy indicate?
    5·1 answer
  • Write a short explanation about the “cheater” way to find the # of valence electrons an element has, and explain what valence el
    5·1 answer
  • What is the theoretical yield of moles of hydrogen that can be produced from 0.032g of MG?
    6·1 answer
  • Frequency of 6.98 x 1013
    8·1 answer
  • All of the following statements concerning voltaic cells are true EXCEPT
    9·1 answer
  • Neon atoms are known to produce a mass spectrum that consists of three peaks at m/z values of 20, 21 and 22, with the relative a
    15·1 answer
  • In a particular type of cat, coat color follows the dominant/recessive pattern of inheritance. The allele for a brown coat (B) i
    5·1 answer
  • What fraction of 2 years is 10 months <br>​
    10·1 answer
  • Which ion below would have the smallest radius?<br> Na+<br> Mg2+<br> 02-<br> F
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!