The decomposition of N2O to N2 and O2 is a first-order reaction. At 730°C, the rate constant of the reaction is 1.94 × 10-4 min-
2 answers:
Answer:
Total pressure 5.875 atm
Explanation:
The equation for above decomposition is
rate constant
Half life
Initial pressure
Pressure after 3572 min = P
According to first order kinematics
solving for P we get
P = 2.35 atm
initial 4.70 0 0
change -2x +2x +x
final 4.70 -2x 2x x
pressure of after first half life = 2.35 = 4.70 - 2x
x = 1.175
pressure of after first half life = 2x = 2(1.175) = 2.35 ATM
Total pressure = 2.35 + 2.35 + 1.175
= 5.875 atm
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Answer:
Explanation:
From the statement of the problem,
B₂S₃ + H₂O
→ H₃BO₃
+ H₂S
B₂S₃ + H₂O → H₃BO₃ + H₂S
We that the above expression does not conform with the law of conservation of mass:
To obey the law, we need to derive a balanced reaction equation:
Let us use the mathematical method to obtain a balanced equation.
let the balanced equation be:
aB₂S₃ + bH₂O → cH₃BO₃ + dH₂S
where a, b, c and d will make the equation balanced.
Conservating B: 2a = c
S: 3a = d
H: 2b = 3c + 2d
O: b = 3c
if a = 1,
c = 2,
b = 6,
2d = 2(6) - 3(2) = 6, d = 3
Now we can input this into our equation:
B₂S₃ + 6H₂O → 2H₃BO₃ + 3H₂S
B₂S₃ + 6H₂O
→ 2H₃BO₃
+ 3H₂S