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Leto [7]
3 years ago
12

Write chemical equation for the following reactions. Indicate physical states and write net ionic equations. If no reaction indi

cate so.
Potassium carbonate + ammonium chloride
Chemistry
1 answer:
iren [92.7K]3 years ago
7 0

There is no reaction.

<em>Molecular equation :</em>

K₂CO₃(aq) + 2NH₄Cl(aq) ⟶ 2KCl(aq) + (NH₄)₂CO₃(aq)

<em>Ionic equation :</em>

2K⁺(aq) + CO₃²⁻(aq) + 2NH₄⁺(aq) +2Cl⁻(aq) ⟶ 2K⁺(aq) + 2Cl⁻(aq) + 2NH₄⁺(aq) + CO₃²⁻(aq)

<em>Net ionic equation :</em>

Cancel all ions that appear on both sides of the reaction arrow (underlined).

<u>2K⁺(aq)</u> + <u>CO₃²⁻(aq)</u> + <u>2NH₄⁺(aq</u>) +<u>2Cl⁻(aq)</u> ⟶ <u>2K⁺(aq)</u> + <u>2Cl⁻(aq</u>) + <u>2NH₄⁺(aq)</u> + <u>CO₃²⁻(aq)</u>

<em>All ions cancel</em>. There is no net ionic equation.

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Explanation:

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Explanation:

The absortion (or liberation) of energy in form of heat is expressed by:

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The information we have:

q=1.30MJ= 1.30*10^6 J

ΔT = 10.0°C = 10.0 K (ΔT is the same in °C than in K)

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If you notice, the Cp in the question is in relation with mol of Na. Before using the q equation, we can find the Cp in relation to the grams of Na.

To do so, we use the molar mass of Na= 22.99g/mol

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Now, we are able to solve for m:

m=\frac{1.30*10^6 J}{1.34\frac{J}{K*g Na} *10.0K}=\frac{1.30*10^6J}{13.4\frac{J}{g Na} }  = 9.70*10^4 g Na=97 Kg Na=97 000 g Na

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Answer: P= 1.64 atm

Explanation: solution attached.

Use Ideal gas law

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