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Tamiku [17]
3 years ago
9

Traveling in a circle requires a net force

Physics
1 answer:
sergij07 [2.7K]3 years ago
4 0
I don’t think I understand the question but true?
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A ball is thrown vertically upward (assumed to be the positive direction) with a speed of 24.0 m/s from a height of 3.0 m. (a) H
SashulF [63]

Answer:

a) 29.36 m

b) 2.44 s

c) 2.57 s

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Explanation:

t = Time taken

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a = Acceleration due to gravity = 9.81 m/s²

b)

v=u+at\\\Rightarrow 0=24-9.81\times t\\\Rightarrow \frac{-24}{-9.81}=t\\\Rightarrow t=2.44 \s

Time taken by the ball to reach the highest point is 2.44 seconds

a)

s=ut+\frac{1}{2}at^2\\\Rightarrow s=24\times 2.44+\frac{1}{2}\times -9.81\times 2.44^2\\\Rightarrow s=29.35\ m

The highest point reached by the ball above its release point is 29.36 m

c) Total height is 3+29.35 = 32.35 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 32.35=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{32.35\times 2}{9.81}}\\\Rightarrow t=2.57\ s

The ball reaches the ground 2.57 seconds after reaching the highest point

d)

v=u+at\\\Rightarrow v=0+9.81\times 2.57\\\Rightarrow v=25.2117\ m/s

The ball will hit the ground at 25.2117 m/s

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