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3 years ago

12

A light bulb is supplied with 100 J of energy each

1 answer:

agasfer [191]3 years ago

8 0

Answer:

a.95J

b.90J

Explanation:

a.Applying energy conservation laws:-

Energy Into Bulb= $Light \ Energy+Thermal \ Energy(Heat \ Energy)$

Given that light energy=5J,and Total Energy=100J

$Heat \ Energy= \Total \ Energy- Light \ Energy\\=100J-5J=95J$

b. Applying the laws in a above.

Total Energy=100J

Light Energy=10J

$Heat \ Energy=100J-10J=90J$

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Two charges, X and Y, are placed along the x-axis. Charge X is +18 nC and is placed at x = 0. Charge Y is placed at a location o

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$k\dfrac{18Q}{x^2} = -k\dfrac{-27Q}{(0.60-x)^2}$

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$x^2+2.40x-0.72 = 0$

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$x = \dfrac{-2.40\pm\sqrt{2.40^2 - (4)(1)(-0.72)}}{2} = \dfrac{-2.40\pm\sqrt{8.64}}{2}$

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