The statement shows a case of rotational motion, in which the disc <em>decelerates</em> at <em>constant</em> rate.
i) The angular acceleration of the disc (
), in revolutions per square second, is found by the following kinematic formula:
(1)
Where:
- Initial angular speed, in revolutions per second.
- Final angular speed, in revolutions per second.
- Time, in seconds.
If we know that
,
y
, then the angular acceleration of the disc is:


The angular acceleration of the disc is
radians per square second.
ii) The number of rotations that the disk makes before it stops (
), in revolutions, is determined by the following formula:
(2)
If we know that
,
y
, then the number of rotations done by the disc is:

The disc makes 3.125 revolutions before it stops.
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Answer:
Option D is correct: 170 µW/m²
Explanation:
Given that,
Frequency f = 800kHz
Distance d = 2.7km = 2700m
Electric field Eo = 0.36V/m
Intensity of radio signal
The intensity of radial signal is given as
I = c•εo•Eo²/2
Where c is speed of light
c = 3×10^8m/s
εo = 8.85 × 10^-12 C²/Nm²
I = 3×10^8 × 8.85×10^-12 × 0.36²/2
I = 1.72 × 10^-4W/m²
I = 172 × 10^-6 W/m²
I = 172 µW/m²
Then, the intensity of the radio wave at that point is approximately 170 µW/m²
I think it is liters, cubic meters, or milliliters.<span />
<span>The SLOPE of a position-time graph represents an object’s SPEED.
It's not possible to tell the object's velocity from the graph, because
the graph doesn't show anything about what direction the object is
moving, and you need to know the direction in order to know the velocity. </span>
Answer:
Her acceleration is 0 m/s²
Explanation:
We note that the motion of the girl is on a straight road, therefore;
The vertical acceleration (e.g. due to gravity, <em>g)</em> on the horizontal motion = 0
The horizontal acceleration, a = (Change in velocity, Δv)/(Change in time, Δt)
For uniform velocity, the change in velocity, Δv = 0
Therefore, fore any change in time, Δt, we have;
a = Δv/Δt
Her acceleration, a = 0/Δt = 0
Her acceleration, a = 0 m/s²