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zhenek [66]
3 years ago
10

For horizontally-launched projectiles, which of the following describes acceleration in both directions with a = 0 and a = -9.8m

/s^2
1. Acceleration is constant in both directions
2. Acceleration is -9.8m/s^2 in both directions
3. Acceleration is zero in both directions
4. Acceleration is equal in both directions ​
Physics
1 answer:
natulia [17]3 years ago
5 0

Answer:

4 is the best option for it as there are some stuff in grade to ye

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Question 2 is because the passengers have inertia, which is a tendency to resist change in motion
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4 years ago
A +15 nC point charge is placed on the x axis at x = 1.5 m, and a -20 nC charge is placed on the y axis at y = -2.0m. What is th
IceJOKER [234]

Answer:E=75\ N/m

Explanation:

Given

First charge of q_1=15\ nC is placed at x=1.5\ m

Second charge  q_2=-20\ nC is placed at y=-2\ m

Electric field is given by

E=\frac{kq}{r^2}

Electric field due to q_1 is away from it

E_1=\frac{9\times 10^9\times 15\times 10^{-9}}{(1.5)^2}

E_1=60\ N/m

Electric field due to q_2

E_2=\frac{9\times 10^9\times 20\times 10^{-9}}{2^2}

E_2=45\ N/m

Net electric field will be vector addition of two

\vec{E_{net}}=\vec{E_1}+\vec{E_2}

\vec{E_{net}}=-60\hat{i}-45\hat{j}

Magnitude of Electric field is

E=\sqrt{60^2+45^2}

E=75\ N/m

8 0
3 years ago
Examine the scenario.
frutty [35]
I Think The answer is d I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
6 0
3 years ago
Read 2 more answers
Starting from a state of no rotation, a cylinder spins so that any point on its edge has a contant tangential acceleration of 3.
Leni [432]

Answer:

Explanation:

tangential acceleration at = 3.1 m  / s²

angular acceleration = tangential accn / radius

= 3.1 / r , r is radius of the cylinder .

IF N₁ be no of rotation in time t

θ = 1/2 α t² , α is angular acceleration , θ is angle in radian covered in time t

2π N₁ = 1/2 (3.1 / r ) x 2.9²

N₁ = 2.0757 / r

similarly we can calculate

2πN₂ = 1/2 (3.1 / r ) x 10²

N₂ = 24.68 / r

N₂ / N₁ = 11.89

3 0
3 years ago
An ostrich can rub at speeds of up 72 km/h. How long will it take (in seconds) an ostrich to run 1.5 km at this top speed
mamaluj [8]

Answer:

A:75 seconds

Explanation:

1.5 km/72 km/h = 0 0208 h = 1.25 minutes = 75 seconds

7 0
3 years ago
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