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Dafna11 [192]
3 years ago
13

Imagine you are going to eat your lunch soon. How did that stuff you eat originally get transformed into food by the plants or a

nimals in the first place?
Chemistry
2 answers:
alexdok [17]3 years ago
6 0
It got planted and went into the process of the specific foot item
tatyana61 [14]3 years ago
6 0

Answer:

what is the question ? please tell me

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Who developed the orbital model of the atom?
Nataliya [291]

Answer:

Ernest Rutherford

Explanation:

that's I think

7 0
3 years ago
Which property determine am atoms ability to attract electrons shared in a chemical bond?
brilliants [131]
Hello there!

Electronegativity is what determine's an atoms ability to attract electrons shared in a chemical bond.Ionization, atomic radius, and also <span> ionic radius both would not determine this as they wouldn't have any similar bond that would attract.
</span><span>
Your correct answer would be (option c)

</span><span>A. ionization 

B. atomic radius

C. electronegativity

D. ionic radius

I hope this helps you!</span>
8 0
3 years ago
There are 9.88x1023 molecules of O2 available.
blondinia [14]

Answer:

1.64 moles O₂

Explanation:

Part A:

Remember 1 mole of particles = 6.02 x 10²³ particles

So, the question becomes, how many  '6.02 x 10²³'s are there in 9.88 x 10²³ molecules of O₂?

This implies a division of given number of particles by 6.02 x 10²³ particles/mole.

∴moles O₂ = 9.88 x 10²³ molecules O₂ / 6.02 x 10²³ molecules O₂ · mole⁻¹ = 1.64 mole O₂

_______________

Part B needs an equation (usually a combustion of a hydrocarbon).

7 0
2 years ago
If 1.35 g of aluminum occupies 0.500 cm^3. what is the density of aluminum
qaws [65]

Answer:

2.7

Explanation:

Density= mass/volume

= 1.35/0.500

= 2.7

6 0
3 years ago
If a substance has a half-life of 55.6 s, and if 230.0 g of the substance are present initially, how many grams will remain afte
Assoli18 [71]

Answer:

m=0.127g

Explanation:

Hello,

In this case, for a first-order reaction, we can firstly compute the rate constant from the given half-life:

k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{55.6s}=0.0125s^{-1}

In such a way, the integrated first-order law, allows us to compute the final mass of the substance once 10.0 minutes (600 seconds) have passed:

m=m_0*exp(-kt)=230.0g*exp(-0.0125s^{-1}*600s)\\\\m=0.127g

Best regards.

6 0
3 years ago
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