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Dafna11 [192]
3 years ago
13

Imagine you are going to eat your lunch soon. How did that stuff you eat originally get transformed into food by the plants or a

nimals in the first place?
Chemistry
2 answers:
alexdok [17]3 years ago
6 0
It got planted and went into the process of the specific foot item
tatyana61 [14]3 years ago
6 0

Answer:

what is the question ? please tell me

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Does 1 gallon or 100 gallons take longer to boil
Ilya [14]

Answer:

it takes 100 gallons longer to boil then it does 1 gallon

Explanation:

brainliest please??

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3 years ago
3 points
vfiekz [6]

Answer:

density=6.74g/ml

:320g÷47.5ml

d=6.74g/ml

thank you

<em><u>I </u></em><em><u>hope</u></em><em><u> </u></em><em><u>this </u></em><em><u>is </u></em><em><u>helpful</u></em>

8 0
3 years ago
You have a cold and symptoms include a runny nose, fever and coughing. How is your body working together to get rid of the bacte
topjm [15]
Your white blood cells are fighting the pathogen (sickness)
8 0
4 years ago
Read 2 more answers
Calculate the OH− concentration after 53 mL of the 0.100 M KOH has been added to 25.0 mL of 0.200 M HBr. Assume additive vol- um
Andre45 [30]

Answer:

\large \boxed{\text{0.0038 mol/L}}

Explanation:

1. Calculate the initial moles of acid and base

\text{moles of acid} = \text{0.0250 L} \times \dfrac{\text{0.200 mol}}{\text{1 L}} = \text{0.005 00 mol}\\\\\text{moles of base} = \text{0.053 L} \times \dfrac{\text{0.100 mol}}{\text{1 L}} = \text{0.0053 mol}

2. Calculate the moles remaining after the reaction

                   OH⁻     +     H₃O⁺ ⟶ 2H₂O

I/mol:      0.0053       0.005 00

C/mol:    -0.00500   -0.005 00

E/mol:      0.0003              0

We have an excess of 0.0003 mol of base.

3. Calculate the concentration of OH⁻

Total volume = 53 mL + 25.0 mL = 78 mL = 0.078 L

\text{[OH}^{-}] = \dfrac{\text{0.0003 mol}}{\text{0.078 L}} = \textbf{0.0038 mol/L}\\\\\text{The final concentration of OH$^{-}$ is $\large \boxed{\textbf{0.0038 mol/L}}$}

8 0
3 years ago
Can somebody help? Do not answer if you don't know.
blondinia [14]

Answer:

10.8amu

Explanation:

Given parameters:

Abundance of B - 10  = 20% = 0.2

Abundance of B - 11  = 80% = 0.8

Unknown:

Atomic mass of Boron = ?

Solution:

The atomic mass of Boron can be can be calculated using the expression below;

 Atomic mass  = (abundance of B - 10 x mass of isotope B - 10 ) +( abundance of  B - 11 x mass of isotope B- 11)

 Atomic mass  = (0.2 x 10) + (0.8 x 11) = 2 + 8.8  = 10.8amu

5 0
3 years ago
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