Answer : The volume of oxygen at STP is 112.0665 L
Solution : Given,
The number of moles of
= 5 moles
At STP, the temperature is 273 K and pressure is 1 atm.
Using ideal gas law equation :

where,
P = pressure of gas
V = volume of gas
n = the number of moles
T = temperature of gas
R = gas constant = 0.0821 L atm/mole K (Given)
By rearranging the above ideal gas law equation, we get

Now put all the given values in this expression, we get the value of volume.

Therefore, the volume of oxygen at STP is 112.0665 L
It measures the acidity/basic level, that rules A out
hope this helped a little
Right answer is option d that o is oxidized.
Hey there!:
Amount of purified acid phosphatase added to tube A = 5 ug ( micrograms )
Amount of acid phosphatase present in 400 ug of wheat germ extract in tube B :
1 / 100 = 5x / 400 =
100 x = ( 0.5 ) ( 400 ) =
x = (0.5 ) ( 400 ) = 100
x = 200 / 100
x = 2 ug
The amount of acid phosphatase present in 400 ug of the wheat germ in tube B is 2 ug
Hope that helps!