Answer:
Hg+2 + 2Cl- -> HgCl2
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Explanation:
Answer:

Explanation:
Hello,
In this case, the molecular chemical reaction is written as:

In such a way, considering the net ionic notation and the solid yielded copper (I) bromide, we write:

Whereas ammonium and sulfate ions are spectator ions, therefore the net ionic equation is:

Regards.
The answer & explanation for this question is given in the attachment below.