Answer:
the mass of the body is 0.02 kg.
Explanation:
Given;
relative density of the oil, = 0.875
mass of the object in oil, = 0.013 kg
mass of the object in water, = 0.012 kg
let the mass of the object in air =
weight of the oil,
weight of the water,
The relative density of the oil is given as;
Therefore, the mass of the body is 0.02 kg.
Answer:
Option C is correct
Explanation:
A supersaturated solution is one that has more solute dissolved than the solution should hold at that temperature.
Examples include carbonated water, sugar syrup, honey.
A solution of a chemical compound can be dissolved in heated water to prepare a supersaturated solution. A solution becomes supersaturated as its temperature is changed.
Answer:
1.dr/dt=0.0096cm/s
2. dA/dt=2.19cm^2/s
Explanation:
A spherical balloon is deflating at 10 cm3/s. At what rate is the radius changing when the volume is 1000π cm3 ? What is the rate of change of surface area at this moment?
for this question, we need to analyze the parameters we know
V=volume of the spherical balloon 1000π cm3
volume of the sphere=
1000π=4/3πr^3
dividing both sides by 4
250*3=r^3
r=9.08cm, the radius of the balloon
dv/dt=dv/dr*dr/dt...................................1
dv/dr ,means
V=
dv/dr=4*pi*r^2
dv/dt=10 cm3/s
from equ 1
10=4*pi*9.08^2*dr/dt
10=1036 dr/dt
dr/dt=10/1036
dr/dt=0.0096cm/s
2. to find the rate at which the area is changing we have,
dA/dt=dA/dr*dr/dt
area of a sphere is 4πr^2
differentiate a with respect to r, radius
dA/dr=8πr
dA/dt=8πr*0.0096
dA/dt=8*pi*9.08*0.0096
dA/dt=2.19cm^2/s
is the rate of change of the surface area
Momentum = (mass) x (speed)
3300 kg-m/s = (61 kg) x (speed)
Speed = (3300 kg-m/s) / (61 kg)
Speed = 54.1 m/s (about 121 mph)
The organisms that belong to the soil food chain, yet do not obtain energy directly from plants are the <span>protozoa.</span>