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Arisa [49]
3 years ago
13

True or false The experimental group is the group that is left alone during the experiment

Chemistry
2 answers:
jolli1 [7]3 years ago
8 0
I’m pretty sure the answer is False
mariarad [96]3 years ago
8 0
False i think because that would not make sense
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Using bond lengths in Table 9.2 (p. 371) and assuming ideal geometry, calculate each of the following distances:
Fed [463]

<u>158 pm</u> is the distance Between equatorial Fluorine atoms in PF₅<u>(</u>Phosphorus pentafluoride).

<h3>What is Fluorine?</h3>

The chemical element fluorine has an atomic number of 9 and the symbol F. The lightest halogen, it is an extremely poisonous, pale yellow diatomic gas under normal conditions. It is exceedingly reactive and, as the most electronegative element, reacts with all other elements with the exception of argon, neon, and helium.

Fluorine is the 24th most abundant element overall and the 13th most abundant on Earth. In order to decrease the melting temperatures of metal ores for smelting, fluorite, the main mineral source of fluorine, was added. The Latin verb fluo, which means "flow," gave the mineral its name. Fluorite was first described in 1529.

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7 0
2 years ago
Briefly explain why the bulk temperature of the water remains low (at room temperature)
elena55 [62]
If the humidity of the room is low, the water that contacts the air directly could evaporate and takes some energy from the bulk thus decreasing its temperature steadily. This allows the water to have a lower temperature.
4 0
3 years ago
You take a balloon and stick it in a refrigerator. The temperature inside the refrigerator is 4.0 °C and the temperature in your
Kobotan [32]
 First convert the 2 temperatures to  degrees K:
4   + 273  ---> 277   and 22---> 295

So using Charles' Law

V1 / T1  = V2 / T2
0.50 / 295 = V2 / 277

solving for V2 gives a volume of  0.469 L  to nearest milliliter

4 0
3 years ago
Read 2 more answers
A metal entrance door swings freely in the winter, but when
ivann1987 [24]

Answer:

This phenomenon occurs because the door, being metal and leading to changes in temperature, undergoes proportional and morphological changes, metals face expansion and expansion in the presence of heat, called thermal expansion.

On the other hand, against the cold, thermal contraction is suffered, that is why its volume decreases, and it contracts.

Explanation:

The expansion phenomenon of the door is not linear, since it increases its volume in width and height, therefore simultaneously on the entire surface.

When an area or surface expands, it does so by increasing its dimensions in the same proportion. For example, a metal sheet increases its length and width, which means an increase in area. Area dilation differs from linear dilation in that it involves an increase in area.

The area expansion coefficient is the increase in area that a body of a certain substance experiences, with an area equal to unity, as its temperature rises one degree centigrade. This coefficient is represented by the Greek letter gamma.

Regarding shrinkage, a clear example of this is when a metal foundry or a weld shrinks, sometimes it is difficult to understand with examples like these (doors) because it is little noticeable by our eyes and the dimensional changes for our perspective. it is infima.

3 0
3 years ago
Calculate the maximum amount of CO2 that can be produced when 64.0 g of O2 and 64.0 g of CH3OH are mixed for the reaction 2 CH3O
Triss [41]

Answer:

58.7g

Explanation:

From the reaction equation, we can see that 3 moles of oxygen yielded 2 moles of carbon (iv) oxide. Let's keep this for later.

Now, we calculate the actual number of moles of oxygen reacted. This can be calculated as follows.

The number of moles of oxygen reacted = mass of oxygen reacted ÷ molar mass of oxygen molecule.

The mass of oxygen reacted is 64g. Now, the molar mass of the oxygen molecule can be calculated from the atomic mass of the oxygen atom. The atomic mass of the oxygen atom is 16 a.m.u .Hence the molar mass = 2 × 16 = 32g/mol.

The number of moles is thus 64 ÷ 32 = 2 moles.

We now calculate the number of moles of Carbon iv oxide yielded.

As said from the beginning of the equation, 3 moles oxygen yielded 2 moles 2 moles CO2. Hence, moles oxygen will yield (2 ×2) ÷ 3 = 4/3 moles O2.

Now we calculate the mass of CO2 yielded.

The mass is = number of moles of CO2 yielded × molar mass of CO2.

Molar mass of CO2 = 12 + 2(16) = 44g/mol.

The mass is thus = 4/3 × 44 = 58.66667g

5 0
4 years ago
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