Question

You take a balloon and stick it in a refrigerator. The temperature inside the refrigerator is 4.0 °C and the temperature in your house is 22 °C. The balloon had an original volume of 0.50 L. What will be the new volume when you take the balloon out, assuming the pressure remains constant?

Answer 1

 First convert the 2 temperatures to  degrees K:
4   + 273  ---> 277   and 22---> 295

So using Charles' Law

V1 / T1  = V2 / T2
0.50 / 295 = V2 / 277

solving for V2 gives a volume of  0.469 L  to nearest milliliter

Answer 2

Answer:

New volume of the balloon = 0.47 L

Explanation:

Given:

Initial Temperature T1 = 22 C

Initial volume of the balloon, V1 = 0.50 L

Final temperature T2 = 4.0 C

To determine:

Final volume of the balloon, V2

Calculation:

Based on the ideal gas equation, pressure (P), volume (V) and temperature (T) are related as:

$PV = nRT$

where n = number of moles of the gas

R = gas constant

Under conditions of constant P and n, the ideal gas equation becomes:

$V/T = constant$

This is Charles Law which can also be expressed under a given set of initial and final conditions as:

$\frac{V1}{T1} =\frac{V2}{T2}$

$V2 = \frac{V1}{T1} * T2 =\frac{0.50 L*(4.0+273)K}{(22+273)K} =0.47\ L$