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Natalka [10]
3 years ago
7

explain how you can use a speedometer and a clock to tell how far you've traveled in a car if the cars odometer is not working

Physics
1 answer:
astraxan [27]3 years ago
5 0
You multiply your average speed with the time for which you have been traveling 
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I need to know the answer
Phoenix [80]

i think number 1 is D number 2 is B

4 0
3 years ago
An electron moving in the direction of the +x-axis enters a magnetic field. If the electron experiences a magnetic deflection in
algol13

Answer:

- z axis

Explanation:

The magnetic force is perpendicular to its speed and the direction of the magnetic field, its equation being

      F = q v x B

Where the bold indicates vectors, q  is a positive charge,

The way to use this equation is with the rule of the right hand, the thumb points in the direction of the velocity, the other fingers extended in the direction of the magnetic field and the palm is the direction of the force for a positive charge.

Let's apply this to our case the speed is on the x axis and the force in ex. negative Y axis, the other fingers point perpendicular to the sheet, but since the charge is negative the magnetic field enters the sheet, this would be the negative z axis

8 0
4 years ago
A race car makes two and a half laps around a circular track in 3.0 min. what is the car's average angular speed?
qaws [65]
<span>Angular speed = total degree / time As = 360*(2.5) / 3.0 min (60) As = 900 deg / 180 s As =5 Degree / second</span>
5 0
3 years ago
A tank is full of oil weighing 40 lb/ft^3. The tank is an inverted right circular cone (with the base at the top) with a height
krok68 [10]

Answer:

26945.6 ft⋅lbf

Explanation:

Volume of Right Circular Cone = pi*(radius^2)*(height/3)

Pi*(4)*(5/3) = 20.94 ft^3

Density = Mass / Volume

Mass = Density*Volume

Mass = (40)*(20.94)

Mass = 837.6 lb

Work = Force*Height

Force = Mass*Acceleration

Acceleration will be gravitational acceleration

Work = (837.6)*(32.17)*(1)

Work = 26945.6 ft⋅lbf

8 0
3 years ago
8. An unpowered flywheel is slowed by a constant frictional torque. At time t = 0 it has an angular velocity of 200 rad/s. Ten s
allsm [11]

Answer:

a) \omega = 50\,\frac{rad}{s}, b) \omega = 0\,\frac{rad}{s}

Explanation:

The magnitude of torque is a form of moment, that is, a product of force and lever arm (distance), and force is the product of mass and acceleration for rotating systems with constant mass. That is:

\tau = F \cdot r

\tau = m\cdot a \cdot r

\tau = m \cdot \alpha \cdot r^{2}

Where \alpha is the angular acceleration, which is constant as torque is constant. Angular deceleration experimented by the unpowered flywheel is:

\alpha = \frac{170\,\frac{rad}{s} - 200\,\frac{rad}{s} }{10\,s}

\alpha = -3\,\frac{rad}{s^{2}}

Now, angular velocities of the unpowered flywheel at 50 seconds and 100 seconds are, respectively:

a) t = 50 s.

\omega = 200\,\frac{rad}{s} - \left(3\,\frac{rad}{s^{2}} \right) \cdot (50\,s)

\omega = 50\,\frac{rad}{s}

b) t = 100 s.

Given that friction is of reactive nature. Frictional torque works on the unpowered flywheel until angular velocity is reduced to zero, whose instant is:

t = \frac{0\,\frac{rad}{s}-200\,\frac{rad}{s} }{\left(-3\,\frac{rad}{s^{2}} \right)}

t = 66.667\,s

Since t > 66.667\,s, then the angular velocity is equal to zero. Therefore:

\omega = 0\,\frac{rad}{s}

7 0
4 years ago
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