Question

Two asteroids are 75000 m apart one has a mass of 8 x 10^7 kg if the force of gravity between them is 1.14 what is the mass of the asteroid
3.4 x 10^11 kg

8.3 x 10 ^12 kg

1.2 x 10 ^12 kg

1.2 x 10^10 kg

Answer 1

Answer:

1.2 × 10¹² kg

Explanation:

The gravitational attraction between both asteroids can be expressed through Newton's law of universal gravitation.

$F=G\frac{m_{1}.m_{2}}{r^{2} }$

where,

F: gravitational force

G: gravitational constant

m: masses of the asteroids

r: distance between the asteroids

$m_{2}=\frac{F.r^{2}}{G.m_{1}} =\frac{1.14N \times (75,000m)^{2}}{(6.67 \times 10^{-11} N.m^{2}/kg^{2}) \times 8 \times 10^{7}kg } =1.2 \times 10^{12} kg$

Answer 2

I’m going to say B

I hope this helped