1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Veseljchak [2.6K]
3 years ago
7

CF4 + Br2 CBr4 + F2

Chemistry
1 answer:
luda_lava [24]3 years ago
5 0

Answer:

Answers are in the explanation

Explanation:

Based on the reaction:

CF₄ + 2Br₂ → CBr₄ + 2F₂

The mole ratio of CF₄ is:

CF₄:Br₂ = 1:2

CF₄:CBr₄ = 1:1

CF₄:F₂ = 1:2

<em>Moles F2:</em>

Molar mass CF₄: 88.0g/mol

57.0g * (1mol / 88.0g) = 0.6477 moles CF₄ * (2mol F₂ / 1mol CBr₄) =

<h3>1.30 moles F₂</h3><h3 />

<em>Mass Br2:</em>

Molar mass CBr₄: 331.63g/mol

250.0g * (1mol / 331.63g) = 0.7539 moles CBr₄ * (2mol Br₂ / 1mol CF₄) =

1.51 moles Br₂ * (159.808g / mol) =

<h3>241g Br2</h3><h3 /><h3 />

<em>Moles F2:</em>

4.8 moles CF₄ * (2mol F₂ / 1mol CF₄) =

<h3>9.6 moles F₂</h3><h3 />

<em />

You might be interested in
Assume that silver and gold form ideal, random mixtures. Calculate the mass of pure Ag needed to cause an entropy increase of 20
KengaRu [80]

Answer:

m_{Ag}=2,265.9g

Explanation:

Hello!

In this case, since the definition of entropy in a random mixture is:

\Delta S=-n_TR\Sigma[x_i*ln(x_i)]

For this silver-gold mixture we write:

\Delta S=-(n_{Au}+n_{Ag})R\Sigma[\frac{n_{Au}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Au}}{n_{Au}+n_{Ag}} )+\frac{n_{Ag}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Ag}}{n_{Au}+n_{Ag}} )]

By knowing the moles of gold:

n_{Au}=100g*\frac{1mol}{197g} =0.508mol

It is possible to write the aforementioned formula in terms of the variable x representing the moles of silver:

20\frac{J}{mol}=-(0.508+x)8.314\frac{J}{mol*K} \Sigma[\frac{0.508}{0.508+x} *ln(\frac{0.508}{0.508+x} )+\frac{x}{0.508+x} *ln(\frac{x}{0.508+x} )]

Which can be solved via Newton-Raphson or a solver software, in this case, I will provide you the answer:

x=n_{Ag}=21.0molAg

So the mass is:

m_{Ag}=21.0mol*\frac{107.9g}{1mol}\\ \\m_{Ag}=2,265.9g

Best regards!

3 0
3 years ago
!!!!!!!!!!!!!!!????<br> hElP!!!!!!!!!!!!
kakasveta [241]
I think the answer is transparent and translucent
5 0
3 years ago
Read 2 more answers
Refer to the example about diatomic gases A and B in the text to do problems 19 - 27.
soldier1979 [14.2K]

Answer:a

Explanation:

5 0
3 years ago
How is a lithium atom (Li) different from a lithium ion (Li+)?
sdas [7]
<span>Li has fewer electrons than Li+ (protons can't change)
</span>
8 0
3 years ago
Read 2 more answers
A valid lewis structure of __________ cannot be drawn without the central atom violating the octet rule. pf5 pcl3 so3 ccl4 co2
lakkis [162]
The answer will be, so3 since s only need two electrons to complete its octet
8 0
3 years ago
Other questions:
  • Describe how particles of iron (Fe) an oxygen (O2) react to how produce oxide (Fe2O3), also known as rust.
    7·1 answer
  • Which describes interactions between substances and stomata during photosynthesis?
    8·1 answer
  • A student collects 350 mL of a vapor at a temperature of 67°C. The atmospheric pressure at the time of collection is 0.900 atm.
    8·1 answer
  • I need help on this someone please help
    13·1 answer
  • Balancing the following equation. Please use numerical answers
    15·1 answer
  • (M1)(M2)+(M2)(P2)=(12.000000)(.9890)+(13.003354)(.1100)=amu
    15·1 answer
  • Climate Change has been a hot topic in the news, politics, and science. To help clarify the issue, address the following:
    13·1 answer
  • hi, help me please with both number 4 and 5, please be sure of your answer, first to answer gets brainliest!​
    5·1 answer
  • Which of these structures is found in all types of plant and animal cells
    10·1 answer
  • What are the two most common elements found in the universe?​
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!