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2 years ago

Graciella divided her grapes equally among 6 friends. If each friend received 16 grapes how many grapes did Graciella have?

Chemistry

2 answers:

Artemon [7]2 years ago

7 0

Answer:

taiks

Explanation:

DIA [1.3K]2 years ago

3 0

Answer: She had 96 grapes.

Explanation:

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To objects (A and B) of the same temperature are in contact with each other? Which statement is true.

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Que pa’so thosui? Esta bious classa?

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3 years ago

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What two particles must a substance particles exhibit in order to conduct electricity

Tom [10]

Answer:

electron (-) and proton (+)

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3 years ago

When 15.3 g of sodium nitrate, NaNO3,was dissolved in water in a calorimeter, the temperature fell from 25.00oC to 21.56oC. If t

satela [25.4K]

Answer:

20.468 kilo Joules is the enthalpy change when one mole of sodium nitrate dissolves.

Explanation:

Heat lost by solution ad calorimeter = Q

Heat capacity of solution ad calorimeter = C = 1071 J/°C

Change in temperature = ΔT = 21.56°C - 25.00°C = -3.44°C

$Q=C\times Delta T$

$Q=1071 J/^oC\times (-3.44^oC)=-3,684.24 J$

Heat gained by sodium nitrate = -Q = -(-3,684.24 J)=3,684.24 J

Moles of sodium nitrate = $\frac{15.3 g}{85 g/mol}=0.18 mol$

When 0.18 mole of sodium nitrate was dissolved in water 3,684.24 joulesof heat was absorbed by it.

Then heat absorbed by 1 mole of sodium nitrate :

$\frac{3,684.24 J}{0.18}=20,468 J=20.468 kJ$

1 J = 0.001 kJ

20.468 kilo Joules is the enthalpy change when one mole of sodium nitrate dissolves.

8 0

3 years ago

For the reaction ? C6H6 + ? O2 → ? CO2 + ? H2O 42.5 grams of C6H6 are allowed to react with 113.1 grams of O2. How much CO2 will

ziro4ka [17]

Answer:

There will be 143,67g CO2 produced

Explanation:

2 C6H6 + 15 O2 → 12 CO2 + 6 H2O

(42,5 g C6H6) / (78.1124 g C6H6/mol) = 0.54408775 mole C6H6

(113.1 g O2) / (31.9989 g O2/mol) = 3.534496 moles O2

0.54408775 mole of C6H6 would react completely with 0.54408775 x (15/2) = 4.080658 mole O2, but there is more O2 present than that, so O2 is in excess and C6H6 is the limiting reactant.

(0.54408775 mol C6H6) x (12/2) x (44.0096 g/mol) = 143.67 g CO2

3 0

3 years ago

Silver nitrate reacts with calcium to make calcium nitrate and silver. The reaction is exothermic and produces 18.7 kJ/mol of en

denis-greek [22]

Answer:

1.63 kilo Joules of energy will be produced when 14.8 g of silver nitrate react.

Explanation:

$AgNO_3+Ca\rightarrow Ag+CaNO_3,\Delta H_{rxn}=-18.7 kJ/mol$

Mass of silver nitrate = 14.8 g

Moles of silver nitrate = $\frac{14.8 g}{170 g/mol}=0.08706 mol$

According to reaction, when 1 mole of silver nitrate reacts with 1 mole of calcium it gives 18.7 kJ of heat.

Then amount of heat released when 0.08706 moles of silver nitrate reacts :

$0.08706\times 18.7 kJ=1.628 kJ\approx 1.63 kJ$

1.63 kilo Joules of energy will be produced when 14.8 g of silver nitrate react.

6 0

3 years ago