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3 years ago

Graciella divided her grapes equally among 6 friends. If each friend received 16 grapes how many grapes did Graciella have?

Chemistry

2 answers:

Artemon [7]3 years ago

7 0

Answer:

taiks

Explanation:

DIA [1.3K]3 years ago

3 0

Answer: She had 96 grapes.

Explanation:

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Calculate the density of gold (in units of g/mL) if a 5.00 cm cube has a mass of 2.41kg

levacccp [35]

The volume of a 5cm cube is 0.5dm*0.5dm*0.5dm = 0.125dm^3
1dm^3 = 1l
So 0.125dm^3 = 125mL
This gives us 2410/125 = 19.28
So the density of gold is 19.28g/mL
Final check: Gold is indeed 19.3g/mL

5 0

3 years ago

Read 2 more answers

A student measures the length and mass of an object records the link is 45.2 cm convert distance measurement to the correct SI b

VladimirAG [237]

As per the International System of Units is a form of metric system in which distance is expressed in meters.

The given distance is 45.2 cm

Convert centimeter (cm) to SI base unit (meter)

One hundred centimeters is equivalent to one meter

I.e. 100 cm = 1 m

Therefore, the given distance of 45.2 cm =

= 45.2 cm * 1 m/100 cm = 0.452 m

Thus, the correct SI base unit for 45.2 cm = 0.452 m

4 0

4 years ago

Animals breathe oxygen and release carbon dioxide during cellular respiration according to the equation below. How much oxygen i

kifflom [539]

Answer:

14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.

Explanation:

Animals take in oxygen and breathe out carbon dioxide during cellular respiration. The reaction for the metabolism of the food in the animal body is:

$C_6H_{12}O_6 + O_2 \rightarrow 6CO_2 + 6H_2O + Energy$

As can be seen from the reaction stoichiometry that:

6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.

Also,

Given :

Mass of carbon dioxide gas = 120 g

Molar mass of carbon dioxide gas = 44 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus, moles of carbon dioxide are:

$moles_{CO_2} = \frac{120 g}{44 g/mol}$

$moles_{CO_2} = 2.7273 mol$

As mentioned:

6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.

1 mole of carbon dioxide gas can be produced from 1/6 mole of oxygen gas in the process of metabolism of glucose.

2.7273 mole of carbon dioxide gas can be produced from $\frac{1}{6} \times 2.7273$ moles of oxygen gas in the process of metabolism of glucose.