Answer:
1.) 113500J
2.) 237m
Explanation:
Hello!
To solve this exercise follow the following steps, the description and complete process is in the attached image
1. Draw the full sketch of the problem.
2. The work is defined as the product of the trajectory by the force that is parallel to this direction, for this reason to find the work done we multiply the horizontal distance (250m) by the applied force (454N)
3. The potential energy is equal to the product of mass, gravity and height and is equal to the work done by the force applied by the cyclist, of this relationship and using algebra we can find the height that the cyclist climbed
4. We use the sine function to find the diagonal distance using the height and angle of the slope
Answer:
Explanation:
As we know that area of the circle at any instant of time is given as
now in order to find the rate of change in area we will have
here we know that
rate of change of radius is given as
radius of the circle is given as
now we have
Answer:
Sagittarius
Explanation:
The center of the Milky Way galaxy lies in the direction of the Sagittarius constellation, about 26,000 light-years away.
Fnet=fa-fr
=47-23
=24n
W=F∆Xcos°
=24n×0.025cos0
=0.6J
Answer:
11.6532 x 10⁻¹¹ J or 7.3 MeV is given off
Explanation:
Mass of an alpha particle = 4.0026u, ∴ mass of three = 12.0078u
Find the difference in mass.
Mass of three alpha - Mass of Carbon nucleus
12.0078u - 12u = 0.0078u
Since 1u = 1.66 x 10⁻²⁷ kg
Therefore, 0.0078u = 1.2948 x 10⁻²⁷
Now that we know Mass(m) = 1.2948 x 10⁻²⁷ and Speed (c) 3 x 10⁸ m²s⁻²
Formular for Energy ==> E₀ = mc²
E = (1.2948 x 10⁻²⁷) (3 x 10⁸ m²s⁻²)²
E = (1.2948 x 10⁻²⁷) (9 x 10¹⁶) J
E = 11.6532 x 10⁻¹¹ J
Or, if you need your energy in MeV
1 MeV = 1.60x10⁻¹³ J
Just do the conversion by dividing 11.6532 x 10⁻¹¹ J by 1.60x10⁻¹³ J
It will give you 7.3 MeV
