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3 years ago

11

The length of a rectangle is more than three times its width. If the perimeter of the rectangle is 92 meters, find the dimension

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1 answer:

Juliette [100K]3 years ago

4 0

The dimensions are 35 m x 11 m

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GEOMETRY HELP PLEASE

ziro4ka [17]

Answer:

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3 years ago

Lorenzo recorded the favorite food of students in his class. According to the results of the survey, what percent of the student

nalin [4]

Answer:

30%

Step-by-step explanation:

Before starting to solve this question we have to understand the following. 1% is equal to one hundredth of something whole, and can be write as $\frac{1}{100}$ .

Now in order to solve this question we will first have to find a fraction that represent how much student out of the whole class choose hamburgers. We can easily find this fraction since the numerator of the fraction will be equal to the number of people that choose hamburgers and the denominator will be equal to the number of all students in the class. So we get......

$\frac{12}{8 + 12 + 14+6} = \frac{12}{40} = \frac{3}{10}$

Now in order to find out what percentage will this fraction equal to we will have make a fraction with the same value but with a denominator being 100. To do that we will have to understand the following......

$\frac{a}{b} = \frac{am}{bm}$ (m is any number except 0)

The main I idea of this rule is that if we multiply the numerator and the denominator by the same number (any number except 0) we will get a fraction with the same value but with a different denominator and numerator.

So in our case we we do the following.........

(multiply both numerator and the denominator by 10 and we get...)

$\frac{3}{10} = \frac{(3)(10)}{(10)(10)} = \frac{30}{100}$

Now if we go back to what I said at the start of my explanation we will understand that another way of writing down $\frac{30}{100}$ is 30%.

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3 years ago

What is the x-coordinate of the solution to the system?<br> { 2x-3y= -27<br> -3x+2y= 23

UkoKoshka [18]

Answer:

x = 41 and y = 76

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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4 years ago

B) Let g(x) =x/2sqrt(36-x^2)+18sin^-1(x/6)<br><br> Find g'(x) =

jolli1 [7]

I suppose you mean

$g(x) = \dfrac x{2\sqrt{36-x^2}} + 18\sin^{-1}\left(\dfrac x6\right)$

Differentiate one term at a time.

Rewrite the first term as

$\dfrac x{2\sqrt{36-x^2}} = \dfrac12 x(36-x^2)^{-1/2}$

Then the product rule says

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 x' (36-x^2)^{-1/2} + \dfrac12 x \left((36-x^2)^{-1/2}\right)'$

Then with the power and chain rules,

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12\left(-\dfrac12\right) x (36-x^2)^{-3/2}(36-x^2)' \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} - \dfrac14 x (36-x^2)^{-3/2} (-2x) \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12 x^2 (36-x^2)^{-3/2}$

Simplify this a bit by factoring out $\frac12 (36-x^2)^{-3/2}$ :

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-3/2} \left((36-x^2) + x^2\right) = 18 (36-x^2)^{-3/2}$

For the second term, recall that

$\left(\sin^{-1}(x)\right)' = \dfrac1{\sqrt{1-x^2}}$

Then by the chain rule,

$\left(18\sin^{-1}\left(\dfrac x6\right)\right)' = 18 \left(\sin^{-1}\left(\dfrac x6\right)\right)' \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac x6\right)'}{\sqrt{1 - \left(\frac x6\right)^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac16\right)}{\sqrt{1 - \frac{x^2}{36}}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{3}{\frac16\sqrt{36 - x^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18}{\sqrt{36 - x^2}} = 18 (36-x^2)^{-1/2}$

So we have

$g'(x) = 18 (36-x^2)^{-3/2} + 18 (36-x^2)^{-1/2}$

and we can simplify this by factoring out $18(36-x^2)^{-3/2}$ to end up with

$g'(x) = 18(36-x^2)^{-3/2} \left(1 + (36-x^2)\right) = \boxed{18 (36 - x^2)^{-3/2} (37-x^2)}$

5 0

2 years ago