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nikklg [1K]
3 years ago
6

How can we use radioactive sources?

Physics
2 answers:
docker41 [41]3 years ago
5 0

Answer:

Alpha - smoke detectors

Beta - tracers (medical imaging), monitoring the thickness of materials (industry - production of plastics etc.)

Gamma - treating cancer, sterilising medical equipment

DedPeter [7]3 years ago
4 0

Answer:

Today, to benefit humankind, radiation is used in medicine, academics, and industry, as well as for generating electricity. In addition, radiation has useful applications in such areas as agriculture, archaeology (carbon dating), space exploration, law enforcement, geology (including mining), and many others.

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☆ Correct and rewrite the following statements:
kvv77 [185]

Answer:

<h3>e)</h3><h3><u>Question</u><u>:</u><u>-</u></h3>
  • Electroplating is based on magnetic effect of electricity.
<h3><u>Answer</u><u>:</u><u>-</u></h3>
  • <em>It's</em><em> </em><em>incorrect</em><em> </em><em>sentence</em><em> </em>
  • As we know that, while electroplating there are two rods, one becoming cathode and another one becoming anode. During electroplating, when electricity is given through the rods, the anode produces positive ions which gets received at the cathode rod and negative ions produced at cathode collects at anode rod which results to the plating of the desired substance. Here, it is a chemical effect of electricity resulting to plating.

<u>So correct sentence is:</u>

  • <em>Electroplating</em><em> </em><em>is</em><em> </em><em>based</em><em> </em><em>of</em><em> </em><em>chemical</em><em> </em><em>effect</em><em> </em><em>of</em><em> </em><em>electricity</em><em>.</em><em> </em>

<h3>f)</h3><h3><u>Question</u><u>:</u><u>-</u></h3>
  • An electric bulb glows due to the chemical effect of electricity.
<h3><u>Answer</u><u>:</u><u>-</u></h3>
  • <em>It's</em><em> </em><em>incorrect</em><em> </em><em>sentence</em><em> </em>
  • As we know that, in an electric bulb there is a filament. When electricity is given in that filament of the electric bulb, the filament gets intensely heated up and results to the emission of light. Due to this heating of the filament due to electricity the electric bulb glows.

<u>So correct sentence is:</u>

  • <em>A</em><em>n electric bulb glows due to the </em><em>h</em><em>e</em><em>a</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>effect of electricity.</em>
6 0
2 years ago
I need help with 1-7 ASAP
elena55 [62]

Refraction. ... Diffraction. ... EM spectrum. ... Intensity. ... Transverse wave. ... Frequency. ... Compression wave.

5 0
3 years ago
Radio telescopes beam radio waves into space. To calculate the speed of the radio waves in space, which information, if any, is
Anastaziya [24]

Answer:

No more information is needed

Explanation:

Radio waves are electromagnetic energy, lower frequency forms of this type of energy that includes light and cosmic rays on the high frequency end that we are able to detect. So in free space (vacuum), radio waves travel at their fastest velocity, the “speed of light”. The reason for the quotation marks is because when light or radio waves are propagating through matter, we observe them traveling more slowly.

7 0
2 years ago
The iron-rich core of the Moon is thought to be about how many kilometers in diameter?
natka813 [3]
The moon is thought to have an iron-rich core whose radius
is 330 km, plus or minus an uncertainty of 20 km.

That puts its diameter in the range of  620 km to 700 km.
6 0
3 years ago
If the charges attracting each other in the preceding problem have equal magnitudes,show that the magnitude of each charge is 2.
Schach [20]

Answer:

The magnitude of each charge is 2.82\times10^{-6}\ C

Explanation:

Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N.

We need to calculate the magnitude of each charge

Using formula of force

F=\dfrac{kq^2}{r^2}

Where, q = charge

r = separation

Put the value into the formula

20=\dfrac{9\times10^{9}\times q^2}{(6\times10^{-2})^2}

q^2=\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}

q=\sqrt{\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}}

q=2.82\times10^{-6}\ C

Hence, The magnitude of each charge is 2.82\times10^{-6}\ C

6 0
3 years ago
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