Data for CH3COOH(l) + C2H5OH(l) CH3COOC2H5(l) + H2O(l) balance were obtained at 100. The initial concentrations of the reagents

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Data for CH3COOH(l) + C2H5OH(l) CH3COOC2H5(l) + H2O(l) balance were obtained at 100. The initial concentrations of the reagents

are indicated in columns 1 and 2 of the table below and the CH3COOC2H5 concentrations in equilibrium are given in column 3. Calculate H2O and determine the value of KC

Chemistry

1 answer:

Sphinxa [80] · Answer 1 · 2022-04-12T13:56:15+03:00

Answer:

Kc = 3.94

Explanation:

CH₃COOH(g) + C₂H₅OH(g) → CH₃COOC₂H₅(g) + H₂O(g)

Liquids aren't included in the equilibrium constant, but at 100°C, all four compounds are a gas. So the equilibrium equation is:

Kc = [CH₃COOC₂H₅] [H₂O] / ([CH₃COOH] [C₂H₅OH])

Set up an ICE table for each row and calculate the value of Kc. Then average the results. (See picture.)

Kc ≈ (3.919 + 4.012 + 3.902) / 3

Kc ≈ 3.94