Answer: 65.7 gram
Explanation:
To calculate the moles :
![\text{Moles of} I_2=\frac{55.6g}{254g/mol}=0.219moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%7D%20I_2%3D%5Cfrac%7B55.6g%7D%7B254g%2Fmol%7D%3D0.219moles)
According to stoichiometry :
1 mole of
are produced by = 2 moles of ![NaI](https://tex.z-dn.net/?f=NaI)
Thus 0.219 moles of
will be produced by =
of ![NaI](https://tex.z-dn.net/?f=NaI)
Mass of ![NaI=moles\times {\text {Molar mass}}=0.438moles\times 150g/mol=65.7g](https://tex.z-dn.net/?f=NaI%3Dmoles%5Ctimes%20%7B%5Ctext%20%7BMolar%20mass%7D%7D%3D0.438moles%5Ctimes%20150g%2Fmol%3D65.7g)
Thus 65.7 g of NaI, must be used to produce 55.6 g of iodine
Answer:
Explanation:
mass of one atom of helium-4 is one-third the mass of one atom of carbon-12. You can find ... mass He. 1 mole He. 4.00 g He. -= 0.366 g He. 0.0914 mothé x 1 motte. Helium ... How many moles of oxygen atoms are present in 5.00 mol diphos-.
Answer:
enviornmental health perspectives
Explanation:
The balanced reaction that describes reaction of ethylene and oxygen to produce carbon dioxide and water is expressed C2H2(g) + 5/2 O2 (g) = 2cO2 (g)+ h2O(g). We convert first the given data to moles thru PV=nRT. The number of moles of oxygen is 0.6349 moles. One mole of c2h2 reacts with 2.5 moles oxygen. The answer is 0.2539 moles c2h2.
Answer: speed and velocity, but no acceleration
Explanation:
Velocity
and acceleration
are both vector quantities, and as vectors they have magnitude and direction. So, if one of this elements (or both) changes, this quantities also changes.
In the case of velocity, its magnitude is the speed and its direction is to the East.
In the case of acceleration, which is the variation of velocity in time, since
is constabt and the direction is the same, the acceleration is zero.
Therefore:
<h3>
An object that is traveling east at a constant rate has <u>
speed and velocity, but no acceleration.</u></h3>