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Vera_Pavlovna [14]
3 years ago
7

Data for CH3COOH(l) + C2H5OH(l) CH3COOC2H5(l) + H2O(l) balance were obtained at 100. The initial concentrations of the reagents

are indicated in columns 1 and 2 of the table below and the CH3COOC2H5 concentrations in equilibrium are given in column 3. Calculate H2O and determine the value of KC

Chemistry
1 answer:
Sphinxa [80]3 years ago
3 0

Answer:

Kc = 3.94

Explanation:

CH₃COOH(g) + C₂H₅OH(g) → CH₃COOC₂H₅(g) + H₂O(g)

Liquids aren't included in the equilibrium constant, but at 100°C, all four compounds are a gas.  So the equilibrium equation is:

Kc = [CH₃COOC₂H₅] [H₂O] / ([CH₃COOH] [C₂H₅OH])

Set up an ICE table for each row and calculate the value of Kc.  Then average the results.  (See picture.)

Kc ≈ (3.919 + 4.012 + 3.902) / 3

Kc ≈ 3.94

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3 years ago
For the reaction: CH₃OH(g) + heat ↔ CO(g) + 2H₂(g) How will the equilibrium shift if the overall pressure is decreased?
MakcuM [25]

Answer:

To the right

Explanation:

CH₃OH(g) + heat <=> CO(g) + 2H₂(g)

According to Le Chatelier's principle, a decrease in pressure will shift the equilibrium position to the side where there is a higher volume.

From the balanced equation above,

Volume of reactant = 1

Volume of product = 1 + 2 = 3

From the above, we can see that the volume of the gasous product is higher than the volume of the gasous reactant.

Therefore, a decrease in the pressure of the system will shift the equilibrium position to the right.

7 0
3 years ago
A 0.8115 g sample of HCl was placed into a 50 mL volumetric flask and the sample was thoroughly dissolved in water to make 50 mL
inysia [295]

Answer:

Molarity of NaOH solution is 1.009 M

Explanation:

Molar mass of HCl is 36.46 g/mol

Number moles = (mass)/(molar mass)

So, 0.8115 g of HCl = \frac{0.8115}{36.46}moles HCl = 0.02226 moles HCl

1 mol of NaOH neutralizes 1 mol of HCl.

So, if molarity of NaOH solution is S(M) then moles of NaOH required to reach endpoint is \frac{S\times 22.07}{1000}moles

So, \frac{S\times 22.07}{1000}=0.02226

or, S = 1.009

So, molarity of NaOH solution is 1.009 M

5 0
3 years ago
Hydrogen peroxide decomposes to form water and oxygen gas
EleoNora [17]
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7 0
3 years ago
A student plans a two-step synthesis of 1-ethyl-3-nitrobenzene from benzene. The first step is nitration of benzene to give nitr
arlik [135]

Answer:

Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.

Explanation:

The benzene ring in itself does not easily undergo electrophilic substitution reaction. Some groups activate or deactivate the benzene ring towards electrophilic substitution reactions.

-NO2 ia a highly deactivating substituent therefore, Friedel-Crafts alkylation of nitrobenzene does not take place under any conditions.

This reaction scheme is therefore flawed because Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.

7 0
3 years ago
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