Question

After an electric sign is turned on, the temperature of its glass goes from 23.5°C to 65.5°C. The sign’s glass has a mass of 905 grams, and the specific heat capacity of the glass is 0.67 joules/gram degree Celsius. How much heat did the glass absorb? Type the correct answer in the box. Use numerals instead of words. Express your answer to the correct number of significant figures.

Answer 1

The sign's glass absorbed 25466.7 J

Further explanation

Given

The temperature of glass :  23.5 °C to 65.5 °C

mass = 905 g

the specific heat capacity = 0.67 J/g °C

Required

Heat absorbed

Solution

Heat absorbed by sign's glass can be formulated :

$\tt Q=m.c.\Delta T$

ΔT=65.5 - 23.5 = 42

$\tt Q=905\times 0.67\times 42\\\\Q=\boxed{\bold{25466.7~J}}$