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Helga [31]
3 years ago
12

A mixture of nitrogen and argon gas is compressed from a volume of 99.0L to a volume of 51.0L , while the pressure is held const

ant at 61.0atm . Calculate the work done on the gas mixture. Round your answer to 3 significant digits, and be sure it has the correct sign (positive or negative)
Chemistry
1 answer:
vitfil [10]3 years ago
5 0

Answer:

2,93x10³atmL, 2,97x10⁵J

Explanation:

The work done in gas compression under constant pressure is:

W = -P×ΔV

<em>Where W is work done, P is pressure and </em>ΔV <em>is change in volume (Vol.f - Vol.i)</em>

Replacing:

W = -61.0atm×(51.0L - 99.0L)

W = 2928atmL = <em>2,93x10³atmL</em>

In Joules:

2928atmL × (101,325J / 1atmL) = 296680J ≡<em> 2,97x10⁵J</em>

<em></em>

I hope it helps!

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#1Write a balanced chemical equation to show the reaction. Include state symbols.
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Answer:

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