Question

A mixture of nitrogen and argon gas is compressed from a volume of 99.0L to a volume of 51.0L , while the pressure is held constant at 61.0atm . Calculate the work done on the gas mixture. Round your answer to 3 significant digits, and be sure it has the correct sign (positive or negative)

Answer 1

Answer:

2,93x10³atmL, 2,97x10⁵J

Explanation:

The work done in gas compression under constant pressure is:

W = -P×ΔV

Where W is work done, P is pressure and ΔV is change in volume (Vol.f - Vol.i)

Replacing:

W = -61.0atm×(51.0L - 99.0L)

W = 2928atmL = 2,93x10³atmL

In Joules:

2928atmL × (101,325J / 1atmL) = 296680J ≡ 2,97x10⁵J

I hope it helps!