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3 years ago

This is an example of A) alpha decay B) beta decay C) gamma decay D) half-life decay

Physics

1 answer:

bulgar [2K]3 years ago

5 0

Answer:

The answer is option A.

alpha decay

Hope this helps

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How much heat is required to convert solid ice with a mass of 985 g and at a temperature of -29.5 °c to liquid water at a temper

liberstina [14]

Consider, please, this solution:

The final heat is:

Q=Q₁+Q₂+Q₃≈726.116 kJ

All the details are in the attachment.

6 0

3 years ago

A speeding motorist traveling with velocity Vm is spotted by a police car. The police car is initially at rest, but the instant

Svetlanka [38]

Answer:

Explanation:

Given

Let us suppose police car and motorist travel in straight line and police car catches motorist after s distance

Distance travel by motorist

$s=v_mt$ ----1

Distance traveled by Police car

$s=ut+\frac{at^2}{2}$

$s=0+\frac{a_pt^2}{2}$

$s=\frac{a_pt^2}{2}$ ----2

from 1 & 2 we get

$t=\frac{2v_m}{a_p}$

(a)Velocity of Police car after t sec

$v=u+a_pt$

$v=0+a_p\times \frac{2v_m}{a_p}$

$v=2v_m$

(b)time taken by police car is

$t=\frac{2v_m}{a_p}$

(c)Distance travel by police car $=\frac{2v_m^2}{a_p}$

7 0

3 years ago

At what height h above the ground does the projectile have a speed of 0.5v?

maw [93]

Answer:

$h=\dfrac{3v^2}{8g}$

Explanation:

It is given that,

Speed of the projectile is 0.5 v. Let h is the height above the ground. Using the first equation of motion to find it.

$v=u+at$

$v=u-gt$

Initial speed of the projectile is v and final speed is 0.5 v.

$0.5v=v-gt$

$t=\dfrac{v}{2g}$

g is the acceleration due to gravity

Let h is the height above the ground. Using the second equation of motion as :

$h=vt-\dfrac{1}{2}gt^2$

$h=v\dfrac{v}{2g}-\dfrac{1}{2}g(\dfrac{v}{2g})^2$

$h=\dfrac{3v^2}{8g}$

So, the height of the projectile above the ground is $\dfrac{3v^2}{8g}$ . Hence, this is the required solution.

6 0

3 years ago

A mine car (mass=390 kg) rolls at a speed of 0.50 m/s on a horizontal track, as the drawing shows. A 250-kg chunk of coal has a

Nady [450]

Answer:

v=0.60 m/s

Explanation:

Given that

m ₁= 390 kg ,u ₁= 0.5 m/s

m₂ = 250 kg ,u₂ = 0.76 m/s

As we know that if there is no any external force on the system the total linear momentum of the system will be conserve.

Pi = Pf

m ₁u ₁+m₂u₂ = (m₂ + m ₁ ) v

Now putting the values in the above equation

390 x 0.5 + 250 x 0.76 = (390 + 250 ) v

$v=\dfrac{390\times 0.5+250\times 0.76}{390+250}\ m/s$

v=0.60 m/s

Therefore the velocity of the system will be 0.6 m/s.

8 0

3 years ago

Newtons laws of motion

Viktor [21]

Answer:

Law 1. A body continues in its state of rest, or in uniform motion in a straight line, unless acted upon by a force.

Law 2. A body acted upon by a force moves in such a manner that the time rate of change of momentum equals the force.

Law 3. If two bodies exert forces on each other, these forces are equal in magnitude and opposite in direction.

7 0

3 years ago