Answer:
hellooooo :) ur ans is 33.5 m/s
At time t, the displacement is h/2:
Δy = v₀ t + ½ at²
h/2 = 0 + ½ gt²
h = gt²
At time t+1, the displacement is h.
Δy = v₀ t + ½ at²
h = 0 + ½ g (t + 1)²
h = ½ g (t + 1)²
Set equal and solve for t:
gt² = ½ g (t + 1)²
2t² = (t + 1)²
2t² = t² + 2t + 1
t² − 2t = 1
t² − 2t + 1 = 2
(t − 1)² = 2
t − 1 = ±√2
t = 1 ± √2
Since t > 0, t = 1 + √2.  So t+1 = 2 + √2.
At that time, the speed is:
v = at + v₀
v = g (2 + √2) + 0
v = g (2 + √2)
If g = 9.8 m/s², v = 33.5 m/s.
 
        
             
        
        
        
Answer:
Entropy is increasing. Entropy is decreasing. 
Explanation:
The Entropy doesn't change.
 
        
             
        
        
        
Explanation:
The given data is as follows.
             m = 5000 kg,            h = 800 km = 
      ,    r = R + h =
,    r = R + h = 
     kg,   G =
 kg,   G = 
As we know that,
               
                       v = 
And, it is known that formula to calculate angular velocity is as follows.
                
                             v = 
                                = 
                                 = 
Thus, we can conclude that speed of the satellite is  .
.
 
        
             
        
        
        
Answer:
b) 2ft/s
Explanation:
A scalar has only magintude, not direction
6.2m, 3kg, and -100 o C are all scalars because they only have magnitude.
2ft/s is not a scalar because it has a direction.
 
        
             
        
        
        
Answer:
Im gonna say it is answer A:) Hope this helps!
Explanation: