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Studentka2010 [4]
3 years ago
6

A Canadian college student who has taken an astronomy class goes home for the holidays and persuades his parents to let him borr

ow the family car. When he returns, he finds that his parents are very angry with him, claiming he left the garage door open. Yet he remembers that he carefully closed the garage door with the electronic remote control in the car. After consulting with his astronomy instructor, he comes up with an alternative explanation for why the garage door is open. Which of the following is PART of that explanation?
a. The Sun was so bright and high in the sky in December in Canada that it got into his
parents' eyes
b. There was an eclipse of the Sun
c. It was a time of solar maximum, and there had been a big flare on the Sun earlier
d. No aurorae had been seen in the sky for many months
e. The number of sunspots had reached an all-time minimum
c. It was a time of solar maximum, and there had
Physics
1 answer:
katen-ka-za [31]3 years ago
7 0

Answer:

Option C, It was a time of solar maximum, and there had been a big flare on the Sun earlier

Explanation:

It was solar maximum due to which the amount of magnetic flux on the sun's surface rises up

This causes high frequency radio blackouts and interrupt with the communication on earth

Some times they also cause ripple effect in the electronic items as in the remote control used by the college student. They can disrupt the electronic communications.

Hence, option C is correct

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_____reaches the Earth’s surface through ______, then turns into ______.
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Answer:

D

Explanation:

magma comes up from the core and comes out through volcanoes and then is turned into lava.

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How does an airbag help protect a passenger in a car following a car accident?
Roman55 [17]

Answer: A

Explanation:

6 0
2 years ago
Read 2 more answers
Work is the transfer of _______ that occurs when a force makes an object move.
Vlad1618 [11]
I think it is energy
4 0
3 years ago
PLEASE HELP ASAP!!!
musickatia [10]

Answer:

22.2 W

Explanation:

First of all, we calculate the work done by moving the wagon, using the formula:

W=Fdcos \theta

where

F = 20 N is the magnitude of the force

d = 1000 m is the displacement of the wagon

\theta=0^{\circ} is the angle between the direction of the force and of the displacement (assuming the force is applied in the direction of motion)

Substituting, we find

W=(20)(1000)=20,000 J

Now we can find the power generated, which is equal to the ratio between the work done and the time taken:

P=\frac{W}{t}

where

W = 20,000 J

t = 15 min = 900 s

Substituting,

P=\frac{20000}{900}=22.2 W

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