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2 years ago

Which of the following is the best estimate for the capacity of a bottle of salad dressing?

1 answer:

7 0

The best and most correct answer among the choices provided by your question is the first choice.

1 fl oz is the best estimate for the capacity of a bottle of salad dressing.

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1) 35 is what percent of 140 2) 250 is 45% of what number? 3) 74 is what percent of 740? 4) 350 is 50% of what number?

densk [106]

Answer:

1) 25%

2) 555.56

3) 10%

4) 700

Step-by-step explanation:

1) 35 is what percent of 140

This is calculated as:

35/140 × 100

= 25%

2) 250 is 45% of what number?

Let the number be represented as x

This is calculated as:

45% of x = 250

45/100 × x = 250

45x /100 = 250

Cross Multiply

45x = 250 × 100

x = 25000/45

x = 555.55555556

x = 555.56

3) 74 is what percent of 740?

Let the percentage be represented by x

x% × 740 = 74

Divide both side by 740

x% = 74/740

x% = 0.1

Converting to percentage

0.1 × 100 = 10%

4) 350 is 50% of what number?

Let the number the represented by x

This is calculated as:

50% of x = 350

50/100 × x = 350

50x /100 = 350

Cross Multiply

50x = 350 × 100

x = 35000/50

x = 700

x = 555.56

5 0

2 years ago

What is the LCM of 95 and 14

kicyunya [14]

Answer:

LCM of 95 and 14 is 1330

Step-by-step explanation:

refer to the picture for explanation

3 0

2 years ago

Penelope has a birdhouse that is 4 and 9/10 feet

defon

Answer:

The distance between the bird houses are 10.26 feet

Step-by-step explanation:

4 0

2 years ago

A function is given: f (x) = 2x + 3 What is the value of f(-2)?

Nadusha1986 [10]

Answer:

f(-2) = -1

Step-by-step explanation:

-2 is x, so replace x as -2 into the equation

f (-2) = 2(-2) + 3

f (-2) = -4 + 3

f (-2) = -1

5 0

2 years ago

Two students walk in the same direction along a straight path, at a constant speed - one at .90 m/s and the other at 1.90 m/s.a.

anyanavicka [17]

Answer:

a)The second student arrive 7 minutes and 36 seconds sooner

b)They have to walk 598,51 m

Step-by-step explanation:

Speed= Distance/Time

We are looking for time now

Time = Distance/Speed

First student

Time = 780 m/0.90 m/s=866,66 seconds

Second student

Time = 780 m/1.90 m/s=410,52 seconds

Difference=866,66-410,52= 456,14 seconds

In minutes

Difference= 456,14 seconds /60=7 minutes 36 seconds

Distance=Speed x Time

Speed¹ x Time¹ =Speed² x Time²

Time¹= Time² + 5.50 min

5.50 min =350 seconds

Time² =Speed¹ x Time¹ /Speed²

Time² =Speed¹ x (Time² + 350 seconds ) /Speed²

Time² =0.9 x (Time² + 350 seconds ) /1.9

Time² =0,4737 x (Time² + 350 seconds )

Time² =0,4737 Time² + 165,79 seconds

Time² - 0,4737 Time² = 165,79 seconds

0,5263 Time² = 165,79 seconds

Time² = 165,79 seconds/0,5263 =315,01 seconds

Distance=1,9 x 315,01 seconds = 598,51 m

5 0

2 years ago