Answer:
option C: B = 0.48; b = 0.52
Explanation:
Of the 50 mice, 12 were homozygous black (BB), 24 were heterozygous black (Bb), and 14 were brown (bb).
BB Bb bb Total
12 + 24 + 14 = 50
the formular for alleleic frequency (p) is (BB+ Bb/2) / total,
q = (bb + Bb/2) / total
Allelic frequecy of B (p) is (12 + 24/2) /50 = 12 + 12 = 24/50 = 0.48
Allelic frequency of b (q) is (14 + 24/2) / 50= 14 + 12 = 26/50 = 0.52
check p + q = 1; 0.48 + 0.52 = 1
3 solid waste and depletion of resources
Hey there!
The purpose of guard cells is to control the opening and closing of the Stomata, keeping it the correct width, or size.
Therefore, your correct answer would be Option 3, control the size of the Stomata.
Hope this helps!
Answer:
A
EXPLANATION:
None