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s2008m [1.1K]
3 years ago
9

A typical raindrop is much more massive than a mosquito and falling much faster than a mosquito flies. How does a mos quito surv

ive the impact? Recent research has found that the collision of a falling raindrop with a mosquito is a perfectly inelastic collision. That is
Physics
1 answer:
Vesnalui [34]3 years ago
7 0

Answer:

Explanation:

Momentum is conserved in an inelastic collision. In a completely-inelastic collision, both objects have a common final velocity.  Once the relative speed between the mosquito and the raindrop is zero, the mosquito is able to detach from the drop and escape

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The nebular hypothesis is the name of the theory where gravitational attraction caused bits of matter to collapse, eventually forming a solar system.
Hope this helps :)
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2 years ago
What is the precision for each measurement for the online simulation. What would be the precision for force
zimovet [89]

Answer:

Unit of precision for force is the Newton.

Explanation:

It is the official unit used to describe force in science and mostly abbreviated with the symbol N.

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Questions:<br>(a) Why should the amplitude of oscillation be small on a pendulum experiment​
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3 years ago
An Atwood's machine consists of two different masses, both hanging vertically and connected by an ideal string which passes over
Tasya [4]

Answer:

V₁ = √ (gy / 3)

Explanation:

For this exercise we will use the concepts of mechanical energy, for which we define energy n the initial point and the point of average height and / 2

Starting point

    Em₀ = U₁ + U₂

    Em₀ = m₁ g y₁ + m₂ g y₂

Let's place the reference system at the point where the mass m1 is

     y₁ = 0

    y₂ = y

    Em₀ = m₂ g y = 2 m₁ g y

End point, at height yf = y / 2

    E_{mf} = K₁ + U₁ + K₂ + U₂

    E_{mf} = ½ m₁ v₁² + ½ m₂ v₂² + m₁ g y_{f} + m₂ g y_{f}

Since the masses are joined by a rope, they must have the same speed

     E_{mf} = ½ (m₁ + m₂) v₁² + (m₁ + m₂) g y_{f}

   E_{mf}= ½ (m₁ + 2m₁) v₁² + (m₁ + 2m₁) g y_{f}

How energy is conserved

   Em₀ =  E_{mf}

   2 m₁ g y = ½ (m₁ + 2m₁) v₁² + (m₁ + 2m₁) g y_{f}

   2 m₁ g y = ½ (3m₁) v₁² + (3m₁) g y / 2

   3/2 v₁² = 2 g y -3/2 g y

   3/2 v₁² = ½ g y

   V₁ = √ (gy / 3)

5 0
2 years ago
What provides the centripetal force needed to keep Earth in orbit?
kkurt [141]
The centripetal force needed to keep earth in orbit is gravity.
3 0
3 years ago
Read 2 more answers
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