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3 years ago

Find the 7th term of the geometric sequence1/8, 1/2, 2, ...

Physics

1 answer:

schepotkina [342]3 years ago

5 0

Answer:

512

Explanation:

Given sequence:

1/8, 1/2, 2, ...

Unknown:

The 7th term of the geometric sequence = ?

Solution:

To solve this problem, we apply the formula below;

Sₙ = arⁿ⁻¹

a is the first term

r is the common ratio

n is the nth term

r = $\frac{\frac{1}{2} }{\frac{1}{8} }$ = $\frac{1}{2} x 8$ = 4

Input the parameters and solve;

Sₙ = $\frac{1}{8}$ x 4⁷⁻¹

Sₙ = $\frac{1}{8}$ x 4⁶ = 512

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Which instrument produces the sound of a single frequency?

notka56 [123]

NO musical instrument produces a 'pure' tone with only a
single frequency in it.

EVERY instrument produces more or less harmonics (multiples)
in addition to the basic frequency it's playing.

The percussion instruments (drums etc) are the richest producers
of bunches of different frequencies.

Fuzzy electric guitars are next richest.

The strings and brass instruments are moderate producers of
harmonics ... I can't remember which is greater than the other.

Then come the woodwinds ... clarinet, oboe, etc.

The closest to 'pure' tones of single frequency are the sounds
made by the flute and piccolo, but even these are far from 'pure'.

The only way to get a true single-frequency sound is from an
electronic 'sine wave' generator.

6 0

3 years ago

You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body

stellarik [79]

A) The change in internal chemical energy is $1.15\cdot 10^7 J$

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

$P=Fv$

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

$P=(80)(8.0)=640 W$

The energy output is related to the power by the equation

$P=\frac{E}{t}$

where:

P = 640 W is the power output

E is the energy output

$t = 30 min \cdot 60 = 1800 s$ is the time elapsed

Solving for E,

$E=Pt=(640)(1800)=1.15\cdot 10^6 J$

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

$\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J$