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Shkiper50 [21]
4 years ago
7

Determine where f(x) is discontinuous. Justify your answer. f(x)=x^2+x-2/x-1

Mathematics
1 answer:
xeze [42]4 years ago
8 0

Answer:x=1

Step-by-step explanation:

Given

F(x)=\dfrac{x^2+x-2}{x-1}

F(x) will be discontinuous at x=1 because value of f(x) is undefined at that point.

F(x) is defined for all values of x except at x=1

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neonofarm [45]

Answer:

54

Step-by-step explanation:

Number of students travelled by bus = 331 - 7 = 324

Number of students in each bus = 324/6 = 54

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3 years ago
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Let a= x^2 +4. Rewrite the following equation in terms of a and set it equal to zero.
dusya [7]

Answer:


If:

a=x^{2}+4    (1)


And we have to rewrite the following expresion in terms of a:


{(x^{2}+4)}^{2}+32=12x^{2}+48   (2)


Firstly we have to rearrange the right side of equation (2) in terms of  x^{2}+4, factorizing by the common factor:


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Then, we can substitute x^{2}+4 by a:


a^{2}+32=12a


And set it equal to zero:

a^{2}-12a+32=0>>>>This is the resulting equation


Now, each term of an algebraic expresion (like the equation above) is composed of sign, coefficient, variable and exponent. The terms are separated from each other by the plus sign (+) or the minus sign (-).



In this case, the variable is a and the number that multiplies the variable (the coefficient) is -12, whereas the constant (which is the term with no variable) is 32





6 0
3 years ago
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HELP I WILL GIVE MANY THX AND BRAINLIST (it says high school but im in middle)
Alenkasestr [34]

Answer:

5 * 5 * 5 * 5

Step-by-step explanation:

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6 0
3 years ago
3x+2=5x What is the answer for this solving equations with variables on each side
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3x +2= 5x
-3x
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3 years ago
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What is the value of x in the equation (5^x)^5=5^35
Arada [10]

\bf (5^x)^5=5^{35}\implies 5^{x\cdot 5}=5^{35}\impliedby \begin{array}{llll} \textit{same bases}\\ \textit{same exponents} \end{array}\implies 5x = 35 \\\\\\ x = \cfrac{35}{5}\implies x=7

6 0
3 years ago
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