Answer:
Explanation:
1.
vf = vi + a(t)
vi = 0 m/s
a = 17/13
= 1.3 m/s^2
2.
F = M * a
= 15 * 1.3
= 19.62 N
3.
Normal force, Fn = m * g
= 15 * 9.8 m/s²
= 147 N.
Then find the maximum force of friction, knowing that μs = 0.76
Ff = Fn × μs
= 147 * 0.76
= 111.83 N
Maximum acceleration,
Ff = m × a
111.83 = 15 * a
a = 7.4556 m/s²
4.
In order to find the acceleration for the box, you need to know the net force of the box moving in the x direction and the frictional force, and you will end up with the Force of the vehicle minus the Frictional force (Ff) between the box and the vehicle, resulting your net force in the x direction.
F = m*a and Ff = μ * N
m*a = μk * N
m*a = μk * m * g
a = μk * g
a = 0.61 * 9.81
5.98 m/s^2 for the acceleration of the box on top of the vehicle.
5.
Assuming the box has re settled and is no longer sliding when braking begins and the surface remains horizontal, the maximum negative acceleration will again be
a = -7.4556 m/s².
Answer:
13.33 m/s^2
Explanation:
Velocity^2 then divide that by the radius
Answer:
At 20 °C (68 °F), the speed of sound in air is about 343 metres per second (1,235 km/h; 1,125 ft/s; 767 mph; 667 kn), or a kilometre in 2.9 s or a mile in 4.7 s.
<h3>
<u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u><u>.</u></h3>
The answer is
Ekin = 1/2 * m * v^2
Ekin = 1/2 * 5,4 * 35,2^2
Ekin = 3345,41 j (joule)
Answer:
400 J
Explanation:
Work is done when a force that is applied to an object moves that object.
The work is calculated by multiplying the force by the amount of movement of an object
W = F * d
here the man has to work against the gravitational field. (against his weight)
F =100 N
Work done = F * d
= 100 * 4
= 400 J
