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Licemer1 [7]
2 years ago
7

An object with mass M is attached to the

Physics
2 answers:
zysi [14]2 years ago
8 0

Answer:

W = 5/4 Mgℓ

Explanation:

Sum of forces:

∑F = ma

T − Mg = M (g/4)

T = 5/4 Mg

Work = force × distance

W = Tℓ

W = 5/4 Mgℓ

olchik [2.2K]2 years ago
8 0

Work done by the tension is ⁵/₄ MgL

\texttt{ }

<h3>Further explanation</h3>

Let's recall the Kinetic Energy and Work formula as follows:

\boxed {E_k = \frac{1}{2}mv^2 }

<em>Ek = kinetic energy ( J )</em>

<em>m = mass of object ( kg )</em>

<em>v = speed of object ( m/s )</em>

\texttt{ }

\boxed {W = F d}

<em>W = work done ( J )</em>

<em>F = force ( N )</em>

<em>d = displacement ( m )</em>

Let us now tackle the problem!

\texttt{ }

<u>Given:</u>

acceleration of the object = a = g/4

initial speed of the object = u = 0 m/s

distance traveled = d = L

<u>Asked:</u>

work done by the tension = W = ?

<u>Solution:</u>

We will use Newton's Law of Motion to solve this problem:

\Sigma F = Ma

T - w = Ma

T = w + Ma

T = Mg + M\frac{g}{4}

T = \frac{5}{4}Mg

T L = \frac{5}{4} MgL

W = \frac{5}{4} MgL

\texttt{ }

<h3>Conclusion :</h3>

Work done by the tension is ⁵/₄ MgL

\texttt{ }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Energy

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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

\theta_{max} =18.38^o

b

New  n_{cladding} =1.491

Explanation:

 From the question we are told that

          The refractive index of the core is  n_{core} = 1.497

         The refractive index of the cladding  is   n_{cladding} = 1.421

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      \theta_{max} = 90 - sin^{-1} [\frac{n_{cladding}}{n_{core}} ]

       \theta_{max} = 90 - sin^{-1} [\frac{1.421}{1.497}} ]

      \theta_{max} =18.38^o

Given from the question the the largest angle is  5°

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