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3 years ago

Two wave pulses move toward each other along a rope.

Physics

2 answers:

mojhsa [17]3 years ago

7 0

Answer:

The answer is B. It is the one that has the triangle pointing up on the topside of the rope and seems to be a bit bigger than the other triangles.

Explanation:

lianna [129]3 years ago

3 0

Answer:

The second option with a vertex pointing upwards.

Explanation:

A wave is a disturbance that can be transmitted through a medium without causing a permanent displacement of the particles of the medium. The two types are; longitudinal and transverse.

In transverse wave, the direction of propagation of the wave is perpendicular to the direction of vibration of the particles of the medium. Examples are; water waves, light waves, X-ray etc. While in longitudinal waves, the direction of vibration of the particles is parallel to the direction of propagation of the waves. Examples are; waves in a slinky, waves in a rope, sound waves etc.

A wave in a rope is a form of longitudinal waves. When two wave pulses move toward each other, interference is observed.

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A train is travelling towards the station on a straight track. It is a certain distance from the station when the engineer appli

AleksandrR [38]

Answer:

500 m

Explanation:

t = Time taken

u = Initial velocity = 50 m/s

v = Final velocity = 0

s = Displacement

a = Acceleration = -2.5 m/s²

Equation of motion

$v=u+at\\\Rightarrow 0=50-2.5\times t\\\Rightarrow \frac{-50}{-2.5}=t\\\Rightarrow t=20\ s$

Time taken by the train to stop is 20 seconds

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=50\times 20+\frac{1}{2}\times -2.5\times 20^2\\\Rightarrow s=500\ m$

∴ The engineer applied the brakes 500 m from the station

4 0

3 years ago

A volume of air increases 0.227 m^3 at a net pressure of 2.07 x 10^7 Pa. How much work is done on the air?

aliya0001 [1]

Answer:

The work done on the air is 4.699 x 10⁶ Joules

Explanation:

Given;

increase in air volume, ΔV = 0.227 m³

net pressure of the air, P = 2.07 x 10⁷ Pa

The work done on the air is given by;

W = PΔV

Where;

W is the work done on the air

P is the net pressure

ΔV is the increase in air volume

Substitute the given values and solve for work done;

W = (2.07 x 10⁷ Pa) (0.227 m³)

W = 4.699 x 10⁶ Joules

Therefore, the work done on the air is 4.699 x 10⁶ Joules

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3 years ago

What season is it when the earth axis is tilted so that it is facing toward the sun?

iVinArrow [24]

Summer (but only in the northern hemisphere)

5 0

3 years ago

Read 2 more answers

A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/

Artemon [7]

Complete Question

A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/s2.How much force does she use to pull on the rope

Answer:

The value is $F = 150 \ N$

Explanation:

From the question we are told that

The mass of the man is $m_m = 75 \ kg$

The mass of the woman is $m_f = 100 \ kg$

The acceleration of the man is $a_m = 2.0 \ m/s ^2$

Generally the force which she used to pull the rope is mathematically represented as

$F = m * a$

=> $F = 75 * 2$

=> $F = 150 \ N$

6 0

3 years ago

Conversations with astronauts on lunar walks had an echo that was used to estimate the distance to the Moon. The sound spoken by

dmitriy555 [2]

Answer:

d ≈ 320000 km

Explanation:

Echoes occurs as a result of the bouncing back of sound waves as it impinges on an obstacle. Since the echo covers two distances (i.e forth and back) the distance is written as 2d.

Velocity of radio waves is taken as the speed of light = $3*10^{8}m/s^{2}$

time =2.15s

DISTANCE = VELOCITY *TIME

2d=vt

$d=\frac{vt}{2}$

$d=\frac{3*10^{8}*2.15}{2}$

d= 322500000m

Distance to the moon is approximately 320000km

4 0

3 years ago