If the distance between us and a star is doubled, with everything else remaining the same, the luminosity Group of answer choice
1 answer:
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1) The distance travelled by the electron is
2) The time taken is
Explanation:
1)
The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance travelled
For the electron in this problem,
is the initial velocity
v = 0 is the final velocity (it comes to a stop)
is the acceleration
Solving for s, we find the distance travelled:
2)
The total time taken for the electron in its motion can also be found by using another suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken
Here we have
v = 0
And solving for t, we find the time taken:
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Answer:
Explanation:
using the law of the conservation of the linear momentum:
where is the inicial momemtum and
is the final momentum
the linear momentum is calculated by the next equation
P = MV
where M is the mass and V is the velocity.
so:
where m is the mass of the proton and is the velocity of the proton after the collision,
is the mass of the nucleus and
is the velocity of the nucleus after the collision.
therefore, we can formulate the following equation:
m(270 m/s) = m + 14m
then, m is cancelated and we have:
270 = +
This is a elastic collision, so the kinetic energy K is conservated. Then:
and
Kf =
then,
=
here we can cancel the m and get:
=
now, we have two equations and two incognites:
270 = +
(eq. 1)
=
in the second equation, we have:
36450 = (eq. 2)
from this last equation we solve for as:
and replace in the other equation as:
270 = 14
so,
Vp is negative because the proton go in the -i hat direction.
Finally, replacing this value on eq. 1 we get: