Answer:
The recoil speed of the man and rifle is .
Explanation:
The expression for the force in terms of mg is as follows;
F=mg
Here, m is the mass and acceleration due to gravity.
Rearrange the expression for mass.
Calculate the combined mass of the man and rifle.
Put .
The expression for the conservation of momentum is as follows as;
Here, is the mass of the man and rifle, is the mass of the rifle, are the initial velocities of the man and bullet and are the final velocities of the man and rifle and rifle.
It is given in the problem that a rifle with a weight of 25 N fires a 4.5-g bullet with a speed of 240 m/s.
Convert mass of rifle from gram to kilogram.
Put , , , and .
Therefore, the recoil speed of the man and rifle is .
Answer:pressure = density * acceleration due to gravity * height
H=72.6cm= 0.726m
P=0.726*13.6*10^3*9.8
P=96761.28Pa
Explanation:
Answer:
the action of polarizing or state of being or becoming polarized: such as the action or process of affecting radiation and especially light so that the vibrations of the wave assume a definite form. Polarization, in Physics, is defined as a phenomenon caused due to the wave nature of electromagnetic radiation. There are two types of waves, transverse waves, and longitudinal waves.
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Answer:
Explanation:
Given that
Height of the tree is 3.7m
Therefore yo=3.7m
yox= 0m
The tiger lands 4.8m from the tree
Then, Range x=4.8m
Since she flies horizontally and she lands away from the bottom of the tree, her path will be trajectory as shown in the attachment
Let know the time of flight, using the equation of motion
voy is the initial velocity of the vertical motion of the is the tiger, which is zero at the beginning.
y = y0 + voy*t + ½*g*t²
Given that,
y=3.7m
yo=0m
voy=0m/s
g=9.81m/s²
y = y0 + voy*t + ½*g*t²
3.7=0+0•t+½×9.81×t²
3.7=0+0+4.905t²
3.7=4.905t²
t²=3.7/4.905
t²=0.7543
t=√0.7543
t=0.87sec
Time to reach the ground is
Now to know the initial velocity of the horizontal motion, using equation of motion
x=xo+Voxt
Vox is the horizontal initial velocity of the tiger.
x=xo+Voxt
4.8=0+Vox×0.87
4.8=0+0.87Vox.
4.8=0.87Vox.
Then, Vox=4.8/0.87
Vox=5.52m/s
Then, her initial velocity Vo
Vo=√voy²+vox²
Vo=√0²+5.52²
Vo=√5.52²
Vo=5.52m/s
The initial velocity is 5.52m/s
am sorry i thout this was my question not your answer sorry