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3 years ago

Hoping for funny and stupid answers

Physics

2 answers:

harina [27]3 years ago

6 0

Answer:

ive once eaten octopus.. i dont recommend.. ANYWAY

i would rather shoot spaghetti out of my fingers ofc, that like free food and sneezing meatballs just sounds painful

Explanation:

fenix001 [56]3 years ago

4 0

Answer:

sneeze meatballs because they are great with a lot of other things

Explanation:

I purposely fell down the stairs for no reason at all

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Question 6(Multiple Choice Worth 2 points)

nikklg [1K]

I believe the answer is the first one.

8 0

3 years ago

If voltage , V = 100 + 6 volt and current , I = 10+ 0.2 A , then find <br> percentage error in R.

Akimi4 [234]

Explanation:

As we know, resistance is the ratio of voltage used and current flowing through the circuit. So,

By error calculation

V = 100 ± 6% V

I = 10 ± 0.2% A

∆R/R= (5/100)×100 + (0.2/10)×100

∆R/R=5+2=7%

<h2>So, percentage error in resistance (R) = ± 7%.</h2>

8 0

3 years ago

Please help The position of masses 4kg, 6kg, 7kg, 10kg, 2kg, and 12kg are (-1,1), (4,2), (-3,-2), (5,-4), (-2,4) and (3,-5) resp

Sophie [7]

Answer:

(1.9756, -2.1951)

Explanation:

The center of mass equation is: $x_{cm}$ = $\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}$ , where m represents the masses and x represents the position.

In order to find the coordinates of the center of mass, we need to use this equation for both the x-values and the y-values.

<u>x-values:</u>

<u /> $x_{cm}$ = $\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}$ = $\frac{4(-1)+6(4)+7(-3)+10(5)+2(-2)+12(3)}{4+6+7+10+2+12}$ = $\frac{(-4)+(24)+(-21)+(50)+(-4)+(36)}{41}$ = $\frac{81}{41}$ = 1.9756

<u>y-values:</u>

<u /> $y_{cm}$ = $\frac{m_{1}y_{1} + m_{2}y_{2} + m_{3}y_{3} + m_{4}y_{4} + m_{5}y_{5} + m_{6}y_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}$ = $\frac{4(1)+6(2)+7(-2)+10(-4)+2(4)+12(-5)}{4+6+7+10+2+12}$ = $\frac{(4)+(12)+(-14)+(-40)+(8)+(-60)}{41}$ = $\frac{-90}{41}$ = -2.1951

<u>center of mass:</u>

(1.9756, -2.1951)

6 0

3 years ago

A car advertisement claims their car can go from a stopped position to moving 60 miles per hour in 5 seconds. The advertisement

ASHA 777 [7]

The advertisement is deciribing the car’s acceleration, as it gains speed when moving from 0-60.

4 0

4 years ago

A mountain lion jumps to a height of 3.25 m when leaving the ground at an angle of 43.2°. What is its initial speed (in m/s) as

miss Akunina [59]

Recall that

${v_f}^2={v_i}^2+2a\Delta y$

where $v_i$ and $v_f$ are the lion's initial and final vertical velocities, $a$ is its acceleration, and $\Delta y$ is the vertical displacement.

At its maximum height, the lion has 0 vertical velocity, so we have

$0={v_i}^2-2gy_{\rm max}$

where <em>g</em> is the acceleration due to gravity, 9.80 m/s², and we take the starting position of the lion on the ground to be the origin so that $\Delta y=y_{\rm max}-0=y_{\rm max}$ .

Let <em>v</em> denote the initial speed of the jump. Then

$v_i=v\sin(43.2^\circ)=\sqrt{2\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(3.25\,\mathrm m)}\implies\boxed{v\approx11.7\dfrac{\rm m}{\rm s}}$

6 0

3 years ago