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Digiron [165]
3 years ago
12

5.You are designing the fit for two bearings. For each case, specify the maximum and minimum hole and shaft diameter:a.A journal

bearing and bushing with basic size is 1.25 in that requires a close running fit.b.A ball bearing assembly with basic size 35 mm that requires a locational interference fit.

Engineering
1 answer:
KIM [24]3 years ago
8 0

Answer:

The solution is given in the attachments.

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write an interface downloadable that has a method "geturl" that returns the url of a downloadable object
Scrat [10]

Answer:

I want to believe the program is to be written in java and i hope your question is complete. The code is in the explanation section below

Explanation:

import java.util.Date;

public interface Downloadable {

  //abstract methods

  public String getUrl();

  public Date getLastDownloadDate();

 

}

3 0
3 years ago
What is the value of the energy (in Joules) stored by the mobile phone battery (capacity of 1.8 Ah), if it is rated at 3.7 V
joja [24]

Answer:

E=23,976 J

Explanation:

Given that

I = 1.8 Ah

Voltage =  3.7 V

We know that 1 h = 3600 s

I = 1.8 x 3600 A.s

I=6480 A.s

The energy in Jules given as

E= V. I  

We know that unit of V.I is Watts ( J/s) and when multiple by seconds then we get Joules.

E=3.7 x 6480 Watt.s

E=23,976 J

Therefore the energy in joule will be 23,976 J.

4 0
3 years ago
Read 2 more answers
If you should lose your balance, you should grab onto the turning center to steady yourself.
lisov135 [29]

No/false is the answer

6 0
3 years ago
A flow of 12 m/s passes through a 6 m wide, 2 m deep rectangular channel with a bed slope of 0. 001. If the mean velocity of flo
prohojiy [21]

Answer:

manning's coefficient is 0.0357

Explanation:

Given:

Velocity of flow, v = 12 m/s

Width of the channel, b = 6 m

Depth of the channel, d = 2 m

bed slope, s = 0.001

mean velocity of flow, V = 1 m/s

now, the velocity is given as:

V= \frac{1}{n}R^{\frac{2}{3}}S^{\frac{1}{2}}

where,

n is the manning's coefficient

R is hydraulic mean depth

R = (Area of the channel) / (wetted Perimeter of the channel)

now,

R = (2 × 6) / ((2 × 2) + 6)

or

R = 12 / 10 = 1.2 m

now, on substituting the values in the equation for velocity, we get

1= \frac{1}{n}1.2^{\frac{2}{3}}(0.001)^{\frac{1}{2}}

or

n= 1.2^{\frac{2}{3}}(0.001)^{\frac{1}{2}}

or

n = 0.0357

hence, the value of manning's coefficient is 0.0357

8 0
3 years ago
These tadpoles are confined to a limited environment. What are they all competing for in that environment
Dovator [93]

Answer: to the earth air

Explanation:

5 0
3 years ago
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