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3 years ago

5

Who was the first person to discover wormholes?

2 answers:

valentinak56 [21]3 years ago

8 0

The first who discovered The Einstein Roses bridge it was discovered by Ludwig flamm in 1916 a few months after Schwarzschild published his solution and was rediscovered by Albert Einstein and his colleague Nathan Rosen which was published then in 1935

GarryVolchara [31]3 years ago

6 0

as stated in the other ans, wormhole or its scientific name, Einstein–Rosen bridge, was discovered by Ludwig Flamm in 1916. But note that Flamm's discovery was through a general relativity solution on black hole dimension by Schwarzschild. Both Schwarzschild's solution and Flamm's discovery are purely mathematical - no wormhole in reality has been found so far.

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An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary

Assoli18 [71]

Answer:

The tension in the cable when the craft was being lowered to the seafloor is 4700 N.

Explanation:

Given that,

When the craft was stationary, the tension in the cable was 6500 N.

When the craft was lowered or raised at a steady rate, the motion through the water added an 1800 N.

The drag force of 1800 N will act in the upward direction. As it was lowered or raised at a steady rate, so its acceleration is 0. As a result, net force is 0. So,

T + F = W

Here, T is tension

F = 1800 N

W = 6500 N

Tension becomes :

$T=W-F\\\\T=6500-1800\\\\T=4700\ N$

So, the tension in the cable when the craft was being lowered to the seafloor is 4700 N.

7 0

3 years ago

How can we DESCRIBE force between two charged bodies

disa [49]

Answer:

it depends if the charged bodies have the same charge repulsion will occur if they have different charges they will attract

7 0

3 years ago

Precautions that should be taken when using a light microscope

Crazy boy [7]

Answer:

b

Explanation:

4 0

3 years ago

Newton's law of cooling states that the rate of change of temperature of an object in a surrounding medium is proportional to th

Nastasia [14]

Answer:

$T = 40 + e^{3.68t} e^{2.99}$

Explanation:

The differential equation for given is given as

$\frac{dT}{dt} = - k(T-T_s)$

integrating above equation we have

ln(T-T_s) = -kt + C

At t = 0 , T(0) = 60

$ln(60- 40) = -k\times 0 + C$

2.99 = C

At t =1 , T(1) = 40.49887

$ln(40.49787 - 40) = -k\times 1 + 2.99$

- k = -3.687

So we have

$T- 40 = e^{3.68t + 2.99}$

$T = 40 + e^{3.68t} e^{2.99}$

4 0

3 years ago

Kinematics practice problems Answers: 4. A race car is traveling at +76 m/s when is slows down at -9 m/s2 for 4

arlik [135]

The new velocity after 4 s is 40 m/s

The height of the spaceship above the ground after 5 seconds is 1,127.5 m

The given parameters for the first question;

initial velocity of the car, u = 76 m/s

acceleration of the car, a = - 9 m/s²

time of motion, t = 4 s

The new velocity after 4 s is calculated as;

v = u + at

v = 76 + (-9)(4)

v = 76 - 36

v = 40 m/s

(5)

The given parameters;

height above the ground, h = 500 m

velocity of spaceship, u = 150 m/s

time of motion, t = 5

The height of the spaceship above the ground after 5 seconds is calculated as;

$h_y = h_0 + ut - \frac{1}{2}gt^2\\\\h_y = 500 + (150\times 5) - (0.5\times 9.8 \times 5^2)\\\\h_y = 1,127.5 \ m$

Learn more here: brainly.com/question/24527971

5 0

2 years ago