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Lerok [7]
3 years ago
15

The following voltage drops are measured across three resistors in series: 5.5 V. 8.2 V. and 12,3 V. What is the value of the so

urce voltage to which these resistors arc connected?
Physics
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

26 V

Explanation:

Given:

The three resistors 5.5 V. 8.2 V. and 12,3 V. are connected in series.

Now we have to find out the source voltage  to which these resistors arc connected ?

Solution:

As we know in series the magnitude of current is uniform but the voltage divides between the resistors supplied from source voltage.So the magnitude of source voltage is, 5.5 V + 8.2 V + 12.3 V = 26 V

Hence, the value of the source voltage to which these resistors are connected is  26 V

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D) All of the above

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Answer:

option C

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The correct answer is option C

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8 0
3 years ago
The plates of a spherical capacitor have radii 6.25 cm and 15.0 crn. The space between the two spheres is filled with a material
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Answer:

Capacitance is 0.572×10⁻¹⁰ Farad

Explanation:

Radius = R₁ = 6.25 cm = 6.25×10⁻² m

Radius = R₂ = 15 cm = 15×10⁻² m

Dielectric constant = k = 4.8

Electric constant = ε₀ = 8.854×10⁻¹² F/m

ε/ε₀=k

ε=kε₀

Capacitance\ (C)=\frac{4\pi k\epsilon_0 R_1\times R_2}{R_2-R_1}\\\Rightarrow C=\frac{4\pi 4.8\times 8.854\times 10^{-12}\times 15\times 10^{-2}\times 6.25\times 10^{-2}}{15\times 10^{-2}-6.25\times 10^{-2}}\\\Rightarrow C=0.572\times 10^{-10}\ Farad

∴ Capacitance is 0.572×10⁻¹⁰ Farad

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3 years ago
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<h2>D</h2>

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We have the final answer as

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