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2 years ago

How many grams of o2(g) are needed to completely burn 70.2 g of C3H8(g)

1 answer:

6 0

First you must write a balanced chemical equation.

C3H8 + 5O2 --> 3CO2 + 4H2O

From there, we can set up the stoichiometry equation to solve.

g O2= 70.2 g C3H8 X (1 mol C3H8/44.0962g C3H8) X (5 mol O2/1 mol C3H8) X (31.998g O2/1 mol O2)

Now solve, and you should get 254.7 g O2. Hope this helped!

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The atomic number is based on the number of protons.

chubhunter [2.5K]

It is the atomic mass because you add the protons and neutrons together to get this number

5 0

3 years ago

The chemical properties of calcium are most similar to the chemical properties of

Ket [755]

The answer is (3) Mg because Ca and Mg are in the same group (group 2).
Hope this helps~

3 0

2 years ago

What volume of water (solute) (d = 1.00 g/mL) should be added to 600. mL of ethanol (solvent, C2H5OH) in order to have a solutio

Ugo [173]

Answer: Volume of water to be added is 116 ml.

Explanation:

Elevation in boiling point is given by:

$\Delta T_b=i\times K_b\times m$

$\Delta T_b=T_b-T_b^0=(95.0-78.4)^0C=16.6^0C$ = elevation in boiling point

i= vant hoff factor = 1 (for non electrolyte)

$K_b$ =boiling point constant = $1.22^0C/m$

m= molality

$\Delta T_b=i\times K_b\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}$

Density of solvent = $\frac{\text {mass of solvent}}{\text {Volume of solvent}}$

$0.789g/ml=\frac{\text {mass of solvent(ethanol)}}{600ml}$

${\text {mass of solvent(ethanol)}=473.4g=0.4734 kg$ (1kg=1000g)

Mass of solute (water) = x g

$16.6^0C=1\times 1.22\times \frac{x}{18g/mol\times 0.4734kg}$

$x=116g$

Density of solute = $\frac{\text {mass of solute}}{\text {Volume of solute}}$

$1.0g/ml=\frac{116g}{\text {Volume of solute(water)}}$

${\text {Volume of solute(water)}}=116ml$

Thus the volume of water to be added is 116 ml.

6 0

2 years ago

If the temperature of the helium balloon were increased from 30°C to 35°C and the volume of the balloon only expanded from 0.47L

Andrej [43]

Answer:

R u from ridge?

Explanation:

Mr Wilson trippin

6 0

3 years ago

In a DNA molecule, if 38% of the molecular bases are C (cytosine), what percent of the bases are T (thymine)?

andreyandreev [35.5K]

Answer:

thymine is 19%

Explanation:

Acc to Chargaff's rule, amount of Adenine= amount of Thymine as well as amount of Guanine= amount of Cytosine. Amount left for Thymine and Adenine is 38% now. Since both Adenine and Thymine are, again in equal quantities, so therefore percentage of thymine is 19%.

8 0

3 years ago