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Brilliant_brown [7]
3 years ago
9

Some plants can reproduce both sexually and asexually. Explain one benefit of this dual reproduction capability.

Chemistry
1 answer:
pantera1 [17]3 years ago
8 0

Answer:

An additional advantage of asexual reproduction is that colonization of new habitats may be easier when an individual does not need to find a mate to reproduce. During sexual reproduction the genetic material of two individuals is combined to produce genetically diverse offspring that differ from their parents.

Explanation:

An organism has many benefits for having the ability to reproduce both sexually and asexually. The first of these benefits is that it doesn't have to find a mate in order to reproduce, so it can create offspring by itself, and enable the continuation of its' species.

If you need more help on this subject, don't be afraid to ask me. I'm willing to help.

You might be interested in
Negative radical in the periodic table<br>​
AVprozaik [17]

Answer:

Negative Radicals ---→

1).Flouride =  F⁻

2). Chloride = Cl⁻

3) Bromide = Br⁻

4) Iodide = I⁻

5) Sulphate = SO₄²⁻

6) Oxide = O²⁻

7) Nitride = N³⁻

8) Sulphur = S²⁻

9) Carbide = C⁴⁻

10) Hydroxide = OH⁻

11) Nitrate = NO₃⁻

12) Carbonate = CO²⁻

13) Hydrogen Carbonate = HCO₃⁻

14) Sulphate = SO₄²⁻

15).Sulphite = SO₃³⁻

16) Nitrate = NO₃⁻

17)Nitrite = NO₂⁻

18) Hydrogen Sulphite = HSO₃⁻

19) Hydrogen Sulphate = HSO₄⁻

20) Chromate = CrO₄²⁻

There are lot of Radicals which cannot be easily written. Although some of the Important Radicals which are commonly used are mentioned above.

Hope it helps,

Please mark me as the brainliest

Thank you

7 0
3 years ago
what are the answers for these I did four through 10 but I think I got four through nine wrong because I mixed up the radius and
velikii [3]

Answer:

1) B

2) D

3) A

4) Ga

5) K

6)Po

7) Atomic size increases down the group

8) B<Al<Ga<In<Tl

9)Se<C<Ga

10) ionization energy is the energy required to remove electrons from the outermost shell of an atom.

Explanation:

In the periodic table, the properties of elements reoccur ''periodically'' throughout the table, hence the name 'periodic table'.

Ionization energy increases across the period hence the noble gas He has the highest ionization energy.

Since ionization energy increases across the period, group 1 elements possess the lowest ionization energy.

Since atomic size increases down the group and decreases across the period, gallium is smaller than indium, potassium is smaller than caesium, polonium is smaller than titanium and iodine is larger than bromine.

This explanation above justifies the order of increasing atomic radius of group 13 elements shown in answer number 8 above.

Since atomic size decreases across the period, the order of increasing atomic size shown in answer number 9 above is correct.

Ionization energy is the energy required to remove electrons from the outermost shell of an atom.

6 0
4 years ago
The Arrhenius theory explains the behavior of
Sergio [31]
The correct answer is acids and bases
the arrheius theory, introduced in 1887 by the Swedish scientist Svante Arrhenius<span>, that </span>acids<span> are substances that dissociate in water to yield electrically charged atoms or molecules, called </span>ions<span>, one of which is a </span>hydrogen ion<span> (H</span>+<span>), and that </span>basesionize in water to yield hydroxide ions (OH−). It is now known that the hydrogen ion cannot exist alone in water solution; rather, it exists in a combined state with a water molecule, as the hydronium ion (H3O+<span>). In practice the hydronium ion is still customarily referred to as the hydrogen ion.</span>
8 0
3 years ago
Assuming that you start with 21.4 g of ammonia gas and 18.0 g of sodium metal and assuming that the reaction goes to completion,
Norma-Jean [14]

Answer:

m_{NaNH_2}=30.42gNaNH_2

m_{H_2}=0.783gH_2

Explanation:

Hello,

In this case, the reaction between sodium and ammonia is:

2Na+2NH_3\rightarrow 2NaNH_2+H_2

Thus, as we know the initial masses of both sodium and ammonia, we should first identify the limiting reactant, for which we firstly compute the available moles of sodium:

n_{Na}=18.0gNa*\frac{1molNa}{23.0gNa}=0.783molNa

And the moles of sodium consumed by 21.4 g of ammonia (2:2 mole ratio):

n_{Na}^{\ consumed}=21.4gNH_3*\frac{1molNH_3}{17gNH_3} *\frac{2molNa}{2molNH_3} =1.26molNa

In such a way, since less moles of sodium are available than consumed by ammonia, we can say, sodium is the limiting reactant. Furthermore, the mass of both sodium amide (39 g/mol) and hydrogen gas (2 g/mol) that are produced turn out:

m_{NaNH_2}=0.783molNa*\frac{2molNaNH_2}{2molNa}*\frac{39gNaNH_2}{1molNaNH_2}=30.42gNaNH_2

m_{H_2}=0.783molNa*\frac{1molH_2}{2molNa}*\frac{2gH_2}{1molH_2}=0.783gH_2

Best regards.

3 0
4 years ago
Given the unbalanced equation Ca(s) + Ag+(aq) → Ca2+(aq) + Ag(s), for a reaction, what is being reduced?
frutty [35]

Answer:

Ag^+ is reduced to Ag^0

Explanation:

Based on the equation

Ca+Ag^+=Ca^2+ + Ag

Ca^0 is increased to Ca^2+

And Ag^+ is reduced to Ag^0

3 0
4 years ago
Read 2 more answers
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