Answer:
Negative Radicals ---→
1).Flouride = F⁻
2). Chloride = Cl⁻
3) Bromide = Br⁻
4) Iodide = I⁻
5) Sulphate = SO₄²⁻
6) Oxide = O²⁻
7) Nitride = N³⁻
8) Sulphur = S²⁻
9) Carbide = C⁴⁻
10) Hydroxide = OH⁻
11) Nitrate = NO₃⁻
12) Carbonate = CO²⁻
13) Hydrogen Carbonate = HCO₃⁻
14) Sulphate = SO₄²⁻
15).Sulphite = SO₃³⁻
16) Nitrate = NO₃⁻
17)Nitrite = NO₂⁻
18) Hydrogen Sulphite = HSO₃⁻
19) Hydrogen Sulphate = HSO₄⁻
20) Chromate = CrO₄²⁻
There are lot of Radicals which cannot be easily written. Although some of the Important Radicals which are commonly used are mentioned above.
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Answer:
1) B
2) D
3) A
4) Ga
5) K
6)Po
7) Atomic size increases down the group
8) B<Al<Ga<In<Tl
9)Se<C<Ga
10) ionization energy is the energy required to remove electrons from the outermost shell of an atom.
Explanation:
In the periodic table, the properties of elements reoccur ''periodically'' throughout the table, hence the name 'periodic table'.
Ionization energy increases across the period hence the noble gas He has the highest ionization energy.
Since ionization energy increases across the period, group 1 elements possess the lowest ionization energy.
Since atomic size increases down the group and decreases across the period, gallium is smaller than indium, potassium is smaller than caesium, polonium is smaller than titanium and iodine is larger than bromine.
This explanation above justifies the order of increasing atomic radius of group 13 elements shown in answer number 8 above.
Since atomic size decreases across the period, the order of increasing atomic size shown in answer number 9 above is correct.
Ionization energy is the energy required to remove electrons from the outermost shell of an atom.
The correct answer is acids and bases
the arrheius theory, introduced in 1887 by the Swedish scientist Svante Arrhenius<span>, that </span>acids<span> are substances that dissociate in water to yield electrically charged atoms or molecules, called </span>ions<span>, one of which is a </span>hydrogen ion<span> (H</span>+<span>), and that </span>basesionize in water to yield hydroxide ions (OH−). It is now known that the hydrogen ion cannot exist alone in water solution; rather, it exists in a combined state with a water molecule, as the hydronium ion (H3O+<span>). In practice the hydronium ion is still customarily referred to as the hydrogen ion.</span>
Answer:
Explanation:
Hello,
In this case, the reaction between sodium and ammonia is:
Thus, as we know the initial masses of both sodium and ammonia, we should first identify the limiting reactant, for which we firstly compute the available moles of sodium:
And the moles of sodium consumed by 21.4 g of ammonia (2:2 mole ratio):
In such a way, since less moles of sodium are available than consumed by ammonia, we can say, sodium is the limiting reactant. Furthermore, the mass of both sodium amide (39 g/mol) and hydrogen gas (2 g/mol) that are produced turn out:
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Answer:
Ag^+ is reduced to Ag^0
Explanation:
Based on the equation
Ca+Ag^+=Ca^2+ + Ag
Ca^0 is increased to Ca^2+
And Ag^+ is reduced to Ag^0
