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Anit [1.1K]
4 years ago
6

Name two kinds of longitudinal waves and explain how you know they are longitudinal

Physics
1 answer:
jasenka [17]4 years ago
6 0
First of all Longitudinal waves is a matter in the medium that moves parallel to the direction of the wave travels. 
1st example: sound travels parallel.
2nd example: when you talk you will here your voice again. because all the frequency bounce back to you.

In the other hand Transverse wave matter in the medium moves perpendicular to direction the wave travels.
For example: light is a good example of transverse wave.
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What is the wavelength of a 2.50-kilohertz sound
Alexxx [7]
The formula v=fλ can be used here.

326=2500*λ

Note the 2500 as 2.5kHz is 2.5 thousand Hz.

λ = 326/2500
= 0.1304m = 0.130m
3 0
3 years ago
A rock is suspended by a light string. When the rock is in air, the tension in the string is 51.9 N . When the rock is totally i
Luden [163]

Answer:

\rho _{liquid}=1995.07kg/m^{3}

Explanation:

When the rock is immersed in unknown liquid the forces that act on it are shown as under

1) Tension T by the string

2) Weight W of the rock

3) Force of buoyancy due to displaced liquid B

For equilibrium we have T_{3}+B = W_{rock}

T_{3}+\rho _{Liquid}V_{rock}g=W_{rock}.....(\alpha)

When the rock is suspended in air for equilibrium we have

T_{1}=W_{rock}....(\beta)

When the rock is suspended in water for equilibrium we have

T_{2} + \rho _{water}V_{rock}g=W_{rock}.....(\gamma)

Using the given values of tension and solving α,β,γ simultaneously for \rho _{Liquid} we get

W_{rock}=51.9N\\31.6+1000\times V_{rock}\times g=51.9N\\\\11.4+\rho _{liquid}V_{rock}g=51.9N\\\\

Solving for density of liquid we get

\rho _{liquid}=\frac{51.9-11.4}{51.9-31.6}\times 1000

\rho _{liquid}=1995.07kg/m^{3}

5 0
3 years ago
3. A 3.0 g bullet traveling at a speed of 400 m/s enters a tree and exits the other side with a speed of 200 m/s. Where did the
iragen [17]

Answer:I had two questions: 1) Shouldnt the equation be : Change of internal energy= Change in Ke or KEi +Ui=KEf+Uf .. I cant seem to understand how the change in KE+ Change in Internal Energy equals 0 2) Also, it has a note which says that if the bullet alone was chosen as a system, then work would be done on it and the heat transfer woudl occur. How would one formulate an equation for this?

Explanation:

4 0
3 years ago
The two properties that are<br> parts of refraction are ...
nikdorinn [45]

Answer:

-Relative refractive index– It is the ratio of speed of light in one medium to the speed of light in another medium

-Absolute refractive index– It is the ratio of light in vacuum to the speed of light in another medium.

Explanation:

7 0
3 years ago
An electron remains suspended between the surface of the Earth (assumed neutral) and a fixed positive point charge, at a distanc
DaniilM [7]

To solve this problem we will apply the concept related to the balance of forces. Here the electrostatic force defined by Coulomb's laws must be proportional to the weight of the electron, defined by Newton's second law, so that such balance exists, both can be described as:

F_e = \frac{kq_1q_2}{d^2}

Here,

q_1 = Charge required

q_2 =Charge of electron

d = Distance

k = Coulomb's constant

F_w = mg

Here,

m = mass

g = Gravitational acceleration

In equilibrium the sum  of Force is zero, then,

\sum F = 0

F_e = F_w

\frac{kq_1q_2}{d^2} = mg

\frac{(8.98755*10^9 )(q_1)(1.6*10^{-19})}{8.8^2} = (9.8)(9.10939*10^{-31} )

q_1 = 4.8075*10^{-19}C

Therefore the charge required for this to happen is 4.8075*10^{-19}C

5 0
3 years ago
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